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When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer?.

Solutions for When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, TA (expressed in eV) and de Broglie wavelength λA, The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 V is TB = TA –1.50eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then which is not correct?a)The work function of A is 2.25 eVb)The work function of B is 3.70 eVc)TA = 2.00eVd)TB = 0.5 eVCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.