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A tensile test is performed on a round bar. After fracture, it has been found that the diameter remains approximately same at fracture. The material under test was
- a)Mild steel
- b)Cast iron
- c)Copper
- d)Aluminium
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A tensile test is performed on a round bar. After fracture, it has bee...
Ductile material fails along principal shear plane as they are weak in shear and brittle material fails along principal normal stress.
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A tensile test is performed on a round bar. After fracture, it has bee...
Explanation:
Cast iron
- Cast iron is a brittle material that tends to fracture without significant deformation before failure.
- During a tensile test, cast iron typically fractures along a plane perpendicular to the applied load, resulting in a clean break.
- The fracture surface of cast iron appears granular due to its brittle nature, unlike the fibrous appearance of ductile materials like mild steel or aluminum.
- The fact that the diameter remains approximately the same at fracture in the case of the round bar indicates that the material did not undergo significant necking or deformation before failure, which is characteristic of brittle materials like cast iron.
In contrast:
- Mild steel, copper, and aluminum are ductile materials that exhibit significant deformation and necking before fracture during a tensile test.
- These materials typically show a reduction in diameter at the fracture point due to necking and elongation before failure.
Therefore, based on the given observation that the diameter remains approximately the same at fracture, the material under test is likely to be cast iron.
Cast iron
- Cast iron is a brittle material that tends to fracture without significant deformation before failure.
- During a tensile test, cast iron typically fractures along a plane perpendicular to the applied load, resulting in a clean break.
- The fracture surface of cast iron appears granular due to its brittle nature, unlike the fibrous appearance of ductile materials like mild steel or aluminum.
- The fact that the diameter remains approximately the same at fracture in the case of the round bar indicates that the material did not undergo significant necking or deformation before failure, which is characteristic of brittle materials like cast iron.
In contrast:
- Mild steel, copper, and aluminum are ductile materials that exhibit significant deformation and necking before fracture during a tensile test.
- These materials typically show a reduction in diameter at the fracture point due to necking and elongation before failure.
Therefore, based on the given observation that the diameter remains approximately the same at fracture, the material under test is likely to be cast iron.
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A tensile test is performed on a round bar. After fracture, it has been found that the diameter remains approximately same at fracture. The material under test wasa)Mild steelb)Cast ironc)Copperd)AluminiumCorrect answer is option 'B'. Can you explain this answer?
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