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A car of mass 1000 kg travelling at 32 ms-1 dashes into the rear of a truck of mass 8000 kg moving in the same direction with a velocity of 4 ms-1. After the collision, the car bounces back with a velocity of 8 ms-1. What is the velocity of the truck after the impact?
- a)9 ms-1
- b)4 ms-1
- c)3 ms-1
- d)12 ms-1
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A car of mass 1000 kg travelling at 32 ms-1dashes into the rear of a t...
for the car,
mcar = 1000 kg, ucar = 32 ms-1, vcar = -8 ms-1
mcar = 1000 kg, ucar = 32 ms-1, vcar = -8 ms-1
for truck,
mtruck = 8000 kg, utruck = 4 ms-1, vtruck = ?
mtruck = 8000 kg, utruck = 4 ms-1, vtruck = ?
By conservation of linear momentum,
mcar.ucar + mtruck.utruck = mcar vcar + mtruck.vtruck
⇒ 1000 × 32 + 8000 × 4 = 1000 × (-8) + 8000 × vtruck
⇒ vtruck = 9 ms-1
⇒ 1000 × 32 + 8000 × 4 = 1000 × (-8) + 8000 × vtruck
⇒ vtruck = 9 ms-1
Most Upvoted Answer
A car of mass 1000 kg travelling at 32 ms-1dashes into the rear of a t...
Car and Truck Collision
Given:
Mass of car (m1) = 1000 kg
Initial velocity of car (v1) = 32 m/s
Mass of truck (m2) = 8000 kg
Initial velocity of truck (v2) = 4 m/s
Final velocity of car (v1f) = -8 m/s (negative sign indicates the car bounces back)
To find: Velocity of the truck after the impact (v2f)
Using the principle of conservation of momentum, we can solve this problem.
1. Calculate the initial momentum of the system:
Initial momentum of the system = momentum of car + momentum of truck
Momentum (p) is given by the product of mass and velocity.
Initial momentum of the system = (m1 * v1) + (m2 * v2)
2. Calculate the final momentum of the system:
Final momentum of the system = momentum of car + momentum of truck
Final momentum of the system = (m1 * v1f) + (m2 * v2f)
According to the conservation of momentum, the initial momentum and final momentum of the system should be equal.
(m1 * v1) + (m2 * v2) = (m1 * v1f) + (m2 * v2f)
3. Substituting the given values into the equation:
(1000 kg * 32 m/s) + (8000 kg * 4 m/s) = (1000 kg * -8 m/s) + (8000 kg * v2f)
32000 kg·m/s + 32000 kg·m/s = -8000 kg·m/s + 8000 kg·v2f
64000 kg·m/s = -8000 kg·m/s + 8000 kg·v2f
4. Rearranging the equation to solve for v2f:
8000 kg·v2f = 64000 kg·m/s - 64000 kg·m/s
8000 kg·v2f = 0 kg·m/s
v2f = 0 m/s
Therefore, the velocity of the truck after the impact is 0 m/s.
Given:
Mass of car (m1) = 1000 kg
Initial velocity of car (v1) = 32 m/s
Mass of truck (m2) = 8000 kg
Initial velocity of truck (v2) = 4 m/s
Final velocity of car (v1f) = -8 m/s (negative sign indicates the car bounces back)
To find: Velocity of the truck after the impact (v2f)
Using the principle of conservation of momentum, we can solve this problem.
1. Calculate the initial momentum of the system:
Initial momentum of the system = momentum of car + momentum of truck
Momentum (p) is given by the product of mass and velocity.
Initial momentum of the system = (m1 * v1) + (m2 * v2)
2. Calculate the final momentum of the system:
Final momentum of the system = momentum of car + momentum of truck
Final momentum of the system = (m1 * v1f) + (m2 * v2f)
According to the conservation of momentum, the initial momentum and final momentum of the system should be equal.
(m1 * v1) + (m2 * v2) = (m1 * v1f) + (m2 * v2f)
3. Substituting the given values into the equation:
(1000 kg * 32 m/s) + (8000 kg * 4 m/s) = (1000 kg * -8 m/s) + (8000 kg * v2f)
32000 kg·m/s + 32000 kg·m/s = -8000 kg·m/s + 8000 kg·v2f
64000 kg·m/s = -8000 kg·m/s + 8000 kg·v2f
4. Rearranging the equation to solve for v2f:
8000 kg·v2f = 64000 kg·m/s - 64000 kg·m/s
8000 kg·v2f = 0 kg·m/s
v2f = 0 m/s
Therefore, the velocity of the truck after the impact is 0 m/s.
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A car of mass 1000 kg travelling at 32 ms-1dashes into the rear of a truck of mass 8000 kg moving in the same direction with a velocity of 4 ms-1. After the collision, the car bounces back with a velocity of 8 ms-1. What is the velocity of the truck after the impact?a)9 ms-1b)4 ms-1c)3 ms-1d)12 ms-1Correct answer is option 'A'. Can you explain this answer?
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A car of mass 1000 kg travelling at 32 ms-1dashes into the rear of a truck of mass 8000 kg moving in the same direction with a velocity of 4 ms-1. After the collision, the car bounces back with a velocity of 8 ms-1. What is the velocity of the truck after the impact?a)9 ms-1b)4 ms-1c)3 ms-1d)12 ms-1Correct answer is option 'A'. Can you explain this answer? for Defence 2024 is part of Defence preparation. The Question and answers have been prepared according to the Defence exam syllabus. Information about A car of mass 1000 kg travelling at 32 ms-1dashes into the rear of a truck of mass 8000 kg moving in the same direction with a velocity of 4 ms-1. After the collision, the car bounces back with a velocity of 8 ms-1. What is the velocity of the truck after the impact?a)9 ms-1b)4 ms-1c)3 ms-1d)12 ms-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Defence 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car of mass 1000 kg travelling at 32 ms-1dashes into the rear of a truck of mass 8000 kg moving in the same direction with a velocity of 4 ms-1. After the collision, the car bounces back with a velocity of 8 ms-1. What is the velocity of the truck after the impact?a)9 ms-1b)4 ms-1c)3 ms-1d)12 ms-1Correct answer is option 'A'. Can you explain this answer?.
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