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What is the major product of the E2 reaction of frans-1-bromo-2-methylcylcohexane with strong base?
- a)methylcyclohexene
- b)2-methylcyclohexene
- c)3-methylcyclohexene
- d)4-methylcyclohexene
Correct answer is option 'C'. Can you explain this answer?
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What is the major product of the E2 reaction of frans-1-bromo-2-methyl...
In E2 reaction, strong base takes β-H from side anti to the leaving group, in the present case, on tertiary β-carbon, hydrogen atom is not available in anti position to leaving group, hence elimination occur from other β-carbon although it produces less substituted, less stable alkene.
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What is the major product of the E2 reaction of frans-1-bromo-2-methyl...
Major Product of E2 Reaction of 1-Bromo-2-Methylcyclohexane
1. Reaction Overview:
- The E2 reaction involves the elimination of a hydrogen and a leaving group (bromine in this case) from an alkyl halide in the presence of a strong base.
- The given compound, 1-bromo-2-methylcyclohexane, undergoes an E2 reaction with a strong base.
2. Mechanism:
- The strong base abstracts a proton from the beta-carbon (adjacent to the bromine) in the cyclohexane ring.
- This leads to the formation of a double bond between the beta and gamma carbons, resulting in the elimination of the bromine leaving group.
3. Product Formation:
- In this case, the major product formed after the E2 reaction of 1-bromo-2-methylcyclohexane is 3-methylcyclohexene.
- The double bond is formed between the beta and gamma carbons in the cyclohexane ring, resulting in the formation of 3-methylcyclohexene.
4. Explanation:
- The 3-methylcyclohexene is the major product because it is more stable due to the presence of a methyl group at the 3-position of the cyclohexane ring.
- The stability of the product is determined by the presence of the methyl group, which contributes to the overall stability of the product.
Therefore, the major product of the E2 reaction of 1-bromo-2-methylcyclohexane with a strong base is 3-methylcyclohexene.
1. Reaction Overview:
- The E2 reaction involves the elimination of a hydrogen and a leaving group (bromine in this case) from an alkyl halide in the presence of a strong base.
- The given compound, 1-bromo-2-methylcyclohexane, undergoes an E2 reaction with a strong base.
2. Mechanism:
- The strong base abstracts a proton from the beta-carbon (adjacent to the bromine) in the cyclohexane ring.
- This leads to the formation of a double bond between the beta and gamma carbons, resulting in the elimination of the bromine leaving group.
3. Product Formation:
- In this case, the major product formed after the E2 reaction of 1-bromo-2-methylcyclohexane is 3-methylcyclohexene.
- The double bond is formed between the beta and gamma carbons in the cyclohexane ring, resulting in the formation of 3-methylcyclohexene.
4. Explanation:
- The 3-methylcyclohexene is the major product because it is more stable due to the presence of a methyl group at the 3-position of the cyclohexane ring.
- The stability of the product is determined by the presence of the methyl group, which contributes to the overall stability of the product.
Therefore, the major product of the E2 reaction of 1-bromo-2-methylcyclohexane with a strong base is 3-methylcyclohexene.
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What is the major product of the E2 reaction of frans-1-bromo-2-methylcylcohexane with strong base?a)methylcyclohexeneb)2-methylcyclohexenec)3-methylcyclohexened)4-methylcyclohexeneCorrect answer is option 'C'. Can you explain this answer?
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