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A sum is to be distributed among certain number of persons. Second person gets one rupee more than the first, third person gets two rupees more than the second and the fourth person gets three rupees more than the third and so on. If the first person gets one rupee and the last person 67 rupees, find the number of persons.?
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A sum is to be distributed among certain number of persons. Second per...
Problem:
A sum is to be distributed among a certain number of persons. The second person gets one rupee more than the first, the third person gets two rupees more than the second, the fourth person gets three rupees more than the third, and so on. If the first person gets one rupee and the last person gets 67 rupees, find the number of persons.

Solution:

Let's assume that there are n persons in total.

Step 1: Setting up the problem

Let's denote the amount of money received by the first person as x.
According to the given information, the second person receives one rupee more than the first person, so the second person receives x + 1.
Similarly, the third person receives two rupees more than the second person, so the third person receives x + 1 + 2 = x + 3.
Continuing this pattern, the last person receives 67 rupees, so the last person receives x + (n-1).
We can now create an equation based on the given information.

Step 2: Formulating the equation

The sum of the amounts received by all the persons should be equal to the total amount of money distributed. In this case, the total amount is the sum of the money received by each person, which can be represented as:

x + (x + 1) + (x + 3) + ... + (x + (n-1)) = total amount

Given that the first person receives one rupee, we have x = 1. Substituting this value into the equation, we get:

1 + (1 + 1) + (1 + 3) + ... + (1 + (n-1)) = total amount

Simplifying further, we have:

1 + 2 + 3 + ... + (n-1) = total amount - n + 1

Step 3: Solving the equation

The sum of consecutive numbers from 1 to (n-1) can be calculated using the formula:

Sum = (n-1)(n)/2

Substituting this into the equation, we have:

(n-1)(n)/2 = total amount - n + 1

Since the total amount is 67 rupees, we can substitute it into the equation:

(n-1)(n)/2 = 67 - n + 1

Simplifying further, we get:

n^2 - 3n - 132 = 0

Step 4: Solving the quadratic equation

We can solve the quadratic equation by factoring or using the quadratic formula. Factoring is not possible in this case, so we will use the quadratic formula:

n = (-b ± √(b^2 - 4ac)) / 2a

For the given equation, a = 1, b = -3, and c = -132. Substituting these values into the quadratic formula, we get:

n = (-(-3) ± √
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A sum is to be distributed among certain number of persons. Second person gets one rupee more than the first, third person gets two rupees more than the second and the fourth person gets three rupees more than the third and so on. If the first person gets one rupee and the last person 67 rupees, find the number of persons.?
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