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The energies of activation for forward and reverse reactions for are 180 kJ mol-1 and 200 kJ mol-1, respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by 100 kJ mol-1. The enthalpy change of the reaction (A2 + B2 → 2 AB) in the presence of catalyst will be (in kJ mol-1)
(AIEEE 2007)
  • a)
    300
  • b)
    120
  • c)
    280
  • d)
    20
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The energies of activation for forward and reverse reactions for are ...

Ea (forward) = 180 kJ mol-1
Ea (backward) = 200 kJ mol-1
In the presence of catalyst,
Ea (forward) = 180 - 100 = 80 kJ mol-1
Ea (backward) = 200 - 100 = 100 kJ mol-1
ΔH = Ea (forward) - Ea (backward)
= 80 - 100 
= - 20 kJ mol-1
For the value of enthalpy change of the reaction, negative sign can be neglected.
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The energies of activation for forward and reverse reactions for are 180 kJ mol-1 and 200 kJ mol-1, respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by 100 kJ mol-1. The enthalpy change of the reaction (A2+ B2 2 AB) in the presence of catalyst will be (in kJ mol-1)(AIEEE2007)a)300b)120c)280d)20Correct answer is option 'D'. Can you explain this answer?
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The energies of activation for forward and reverse reactions for are 180 kJ mol-1 and 200 kJ mol-1, respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by 100 kJ mol-1. The enthalpy change of the reaction (A2+ B2 2 AB) in the presence of catalyst will be (in kJ mol-1)(AIEEE2007)a)300b)120c)280d)20Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The energies of activation for forward and reverse reactions for are 180 kJ mol-1 and 200 kJ mol-1, respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by 100 kJ mol-1. The enthalpy change of the reaction (A2+ B2 2 AB) in the presence of catalyst will be (in kJ mol-1)(AIEEE2007)a)300b)120c)280d)20Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energies of activation for forward and reverse reactions for are 180 kJ mol-1 and 200 kJ mol-1, respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by 100 kJ mol-1. The enthalpy change of the reaction (A2+ B2 2 AB) in the presence of catalyst will be (in kJ mol-1)(AIEEE2007)a)300b)120c)280d)20Correct answer is option 'D'. Can you explain this answer?.
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