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trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements.
(1) The second mixture formed is one and a half times heavier than the original mixture.
(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.
(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.
(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.
  • a)
    a,d
  • b)
    b,d
  • c)
    b,c,d
  • d)
    a,c,d
  • e)
    a,b,c,d
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
trader forms a mixture of cement and sand weighing 40 kgs. In the mi...
Initially, Sand = 40/5 = 8kg, Cement = 40/4 = 10kg
Let him add x kgs of Sand to the 40kg mixture.
40+x:8+x = 7:3
3(40+x) = 7(8+x)
So, x = 16kg
(a) New mixture = 56 kgs != 1.5 x 40. So (a) is wrong.
(b) From above, (b) is correct. (c) Sand = 3x40/11 != 12kg. So
(c) is wrong. (d) 7kg sold: So 49 kg remains with 28kg of cement, 21 kg of sand.
11kg 7:4 or 7kg of cement, 4 kg of Sand cement = 28 + 7 = 35kg, Sand = 21 + 4 = 25kg Ratio = 35:25 = 7:5 So
(d) is correct.
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Most Upvoted Answer
trader forms a mixture of cement and sand weighing 40 kgs. In the mi...
Explanation:

Original Mixture:
- Weight of original mixture = 40 kgs
- Ratio of cement to sand = 4 : 1
- Therefore, weight of cement = 4x and weight of sand = x
- 4x + x = 40
- 5x = 40
- x = 8 kgs (weight of sand) and 32 kgs (weight of cement)

Second Mixture:
- New ratio of cement to sand = 4 : 3
- Let weight of sand added = y kgs
- (32 / 8 + y) / (8 + y) = 4 / 3
- Solving, we get y = 16 kgs

Statements:
- In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg. This statement is true as calculated above.
- If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5. This statement is true based on the calculations of the new mixture ratios.
- The second mixture formed is one and a half times heavier than the original mixture. This statement is false as the weight of the second mixture is 56 kgs, which is not one and a half times heavier than the original 40 kg mixture.
- Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg. This statement is false as the weight of sand in the original mixture is 8 kgs.
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trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer?
Question Description
trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer?.
Solutions for trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT. Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free.
Here you can find the meaning of trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice trader forms a mixture of cement and sand weighing 40 kgs. In the mixture, cement and sand are in the ratio of 4 : 1 in weight terms. Later, when he adds more sand to the mixture, the new ratio becomes 4 : 3. Given this, mark the correct statements. (1) The second mixture formed is one and a half times heavier than the original mixture.(2) In order to arrive at the second mixture, the trader had to add a quantity of sand weighing 16 kg.(3) Had the original mixture been in the ratio of 8 : 3, the weight of the sand in the original mixture would have been 12 kg.(4) If the trader sells 7 kg of the second mixture formed by him, and adds 11 kg of a new mixture of cement and sand in the ratio 7 : 4 to the residual, then the new ratio of cement to sand will become 7 : 5.a) a,db) b,dc) b,c,dd) a,c,de) a,b,c,dCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice CAT tests.
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