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On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer?.

Solutions for On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane will be (molar mass of heptane = 100 g mol-1and of octane= 114 g mol-1).(AIEEE2010)a)72.0 kPab)75.0 kPac)52.5 kPad)45.0 kPaCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.