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  as the power series expansion    then a5  correct upto three decimal places, is equal to _
    Correct answer is '0.1'. Can you explain this answer?
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    as the power series expansion then a5correct upto three decimal places...
    We have
    a1x + a2x2 + a3x3 + a4x4 + a5x5 +..
    On differentiation, it gives, by Leibnitz rule on the left, and termwise differentiation on the right,
    ex = 1 +
    cosx
    Then

    The coefficient of t4 in (*) is 5a5.
    The coefficient of x4 in (**) is 1/2 + 1/4!, i.e., 1/2 + 1/24 = 13/24.

    Comparing these coefficients (note that symbols x and t play the same role), we get
    13/24 = 5a5
    Which given a5 = 1/5. 13/24 ≈ 0.108.
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    as the power series expansion then a5correct upto three decimal places...
    We have
    a1x + a2x2 + a3x3 + a4x4 + a5x5 +..
    On differentiation, it gives, by Leibnitz rule on the left, and termwise differentiation on the right,
    ex = 1 +
    cosx
    Then

    The coefficient of t4 in (*) is 5a5.
    The coefficient of x4 in (**) is 1/2 + 1/4!, i.e., 1/2 + 1/24 = 13/24.

    Comparing these coefficients (note that symbols x and t play the same role), we get
    13/24 = 5a5
    Which given a5 = 1/5. 13/24 ≈ 0.108.
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    as the power series expansion then a5correct upto three decimal places, is equal to _Correct answer is '0.1'. Can you explain this answer?
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