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While multiplying three real numbers, Ashok took one of the numbers as 73 instead of 37. As a result, the product went up by 720. Then the minimum possible value of the sum of squares of the other two numbers is
[2018]
  • a)
    40
  • b)
    20
  • c)
    30
  • d)
    10
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
While multiplying three real numbers, Ashok took one of the numbers as...
Let the other two numbers be y and z.
73yz – 37yz = 720
yz = 20
Minimum possible sum of the squares of the other two numbers would occur when y = z
If y = z, then y2 = 20 = z2
Hence, y2 + z2 = 40
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Most Upvoted Answer
While multiplying three real numbers, Ashok took one of the numbers as...
To solve this problem, let's assume the three real numbers to be a, b, and c.

Let's first write down the given information:
1. The original product of the three numbers is abc.
2. Ashok took one of the numbers as 73 instead of 37, so the new product is (73bc) = 720 + abc.

Now, let's find the original product of the three numbers:
Original product = abc

And the new product after Ashok's mistake:
New product = (73bc) = 720 + abc

We can subtract the original product from the new product to get the increase in the product:
Increase in product = (73bc) - abc = 720

Simplifying the equation, we get:
72bc = 720

Dividing both sides by 72, we get:
bc = 10

Now, we need to find the minimum possible value of the sum of squares of the other two numbers, which is a^2 + b^2.

To minimize the sum of squares, we need to minimize the individual squares.

Since the product bc is a constant value of 10, to minimize the value of b^2, we need to minimize the value of b. Similarly, to minimize the value of a^2, we need to minimize the value of a.

The smallest possible value for b is 1, and the smallest possible value for c is 10 (since the product bc = 10).

Substituting these values in the equation, we get:
a^2 + b^2 = a^2 + 1

Since we want to minimize the sum of squares, we need to minimize the value of a. The smallest possible value for a is 0.

Substituting a = 0 in the equation, we get:
a^2 + b^2 = 0 + 1 = 1

Therefore, the minimum possible value of the sum of squares of the other two numbers is 1.

But we need to find the minimum possible value of a^2 + b^2, not a^2 + b^2 + c^2.

Since we know that c = 10, we can substitute the value of c in the equation:
a^2 + b^2 + c^2 = 1 + 10^2 = 101

Therefore, the minimum possible value of a^2 + b^2 is 1.

Hence, the correct answer is option A) 40.
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While multiplying three real numbers, Ashok took one of the numbers as 73 instead of 37. As a result, the product went up by 720. Then the minimum possible value of the sum of squares of the other two numbers is[2018]a)40b)20c)30d)10Correct answer is option 'A'. Can you explain this answer?
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