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Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A is
Correct answer is '12'. Can you explain this answer?
Verified Answer
Point P lies between points A and B such that the length of BP is thri...
Let the distance between A and B be 4x.
Length of BP is thrice the length of AP.
=> AP = x and BP = 3x
Let the speed of car 1 be s and the speed of car 2 be 0.5s.
Car 2 reaches P one hour (60 minutes) after Car 1 reaches P.
=> x/s + 60 = 3x/0.5s
x/s + 60 = 6x/s
5x/s = 60
x/s = 12
Time taken by car 1 in reaching P from A = x/s = 12 minutes.
Therefore, 12 is the correct answer.
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Most Upvoted Answer
Point P lies between points A and B such that the length of BP is thri...
Given information:
- Point P lies between points A and B.
- Length of BP = 3 * Length of AP.
- Car 1 starts from A and moves towards B.
- Car 2 starts from B and moves towards A.
- Car 2 reaches P one hour after car 1 reaches P.
- Speed of car 2 = 1/2 * Speed of car 1.

To find: Time taken by car 1 in reaching P from A.

Let's assume:
- Length of AP = x units.
- Length of BP = 3x units.
- Speed of car 1 = v units/hr.
- Speed of car 2 = 1/2 * v units/hr.

Calculations:
- Time taken by car 1 to reach P from A = Length of AP / Speed of car 1.
- Time taken by car 2 to reach P from B = Length of BP / Speed of car 2.
- Distance traveled by car 1 = AP + BP = x + 3x = 4x units.
- Distance traveled by car 2 = BP = 3x units.

Now we can calculate the time taken by each car using the distance traveled and the speed of each car:

- Time taken by car 1 = Distance traveled by car 1 / Speed of car 1 = (4x units) / (v units/hr) = 4x/v hrs.
- Time taken by car 2 = Distance traveled by car 2 / Speed of car 2 = (3x units) / (1/2 * v units/hr) = 6x/v hrs.

According to the given information, car 2 reaches P one hour after car 1 reaches P. Therefore, the time taken by car 2 is equal to the time taken by car 1 plus 1 hour:

6x/v = 4x/v + 1.

Simplifying the equation:

6x = 4x + v.

2x = v.

Substituting the value of v in the equation for the time taken by car 1:

Time taken by car 1 = 4x/v = 4x/(2x) = 2 hrs.

Converting hours to minutes:

Time taken by car 1 = 2 hrs * 60 min/hr = 120 min.

Therefore, the time taken by car 1 in reaching P from A is 120 minutes or 2 hours.
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Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A isCorrect answer is '12'. Can you explain this answer?
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