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Two elements A and B form compounds AB2 and AB4 (both are non-volatile and non-electrolyte) when dissolved in 20.0 g benzene, 1 g of AB2 lowers the freezing point of benzene by 2.3 K, whereas 1.0 g of AB4 lowers it by 1.3 K [Kf (benzene) = 5.5 K mol-1 kg]. ; Thus, atomic masses of A and B respectively, ara)120,212b)96,28c)212,120d)28,46Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about Two elements A and B form compounds AB2 and AB4 (both are non-volatile and non-electrolyte) when dissolved in 20.0 g benzene, 1 g of AB2 lowers the freezing point of benzene by 2.3 K, whereas 1.0 g of AB4 lowers it by 1.3 K [Kf (benzene) = 5.5 K mol-1 kg]. ; Thus, atomic masses of A and B respectively, ara)120,212b)96,28c)212,120d)28,46Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
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Solutions for Two elements A and B form compounds AB2 and AB4 (both are non-volatile and non-electrolyte) when dissolved in 20.0 g benzene, 1 g of AB2 lowers the freezing point of benzene by 2.3 K, whereas 1.0 g of AB4 lowers it by 1.3 K [Kf (benzene) = 5.5 K mol-1 kg]. ; Thus, atomic masses of A and B respectively, ara)120,212b)96,28c)212,120d)28,46Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Two elements A and B form compounds AB2 and AB4 (both are non-volatile and non-electrolyte) when dissolved in 20.0 g benzene, 1 g of AB2 lowers the freezing point of benzene by 2.3 K, whereas 1.0 g of AB4 lowers it by 1.3 K [Kf (benzene) = 5.5 K mol-1 kg]. ; Thus, atomic masses of A and B respectively, ara)120,212b)96,28c)212,120d)28,46Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Two elements A and B form compounds AB2 and AB4 (both are non-volatile and non-electrolyte) when dissolved in 20.0 g benzene, 1 g of AB2 lowers the freezing point of benzene by 2.3 K, whereas 1.0 g of AB4 lowers it by 1.3 K [Kf (benzene) = 5.5 K mol-1 kg]. ; Thus, atomic masses of A and B respectively, ara)120,212b)96,28c)212,120d)28,46Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Two elements A and B form compounds AB2 and AB4 (both are non-volatile and non-electrolyte) when dissolved in 20.0 g benzene, 1 g of AB2 lowers the freezing point of benzene by 2.3 K, whereas 1.0 g of AB4 lowers it by 1.3 K [Kf (benzene) = 5.5 K mol-1 kg]. ; Thus, atomic masses of A and B respectively, ara)120,212b)96,28c)212,120d)28,46Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Two elements A and B form compounds AB2 and AB4 (both are non-volatile and non-electrolyte) when dissolved in 20.0 g benzene, 1 g of AB2 lowers the freezing point of benzene by 2.3 K, whereas 1.0 g of AB4 lowers it by 1.3 K [Kf (benzene) = 5.5 K mol-1 kg]. ; Thus, atomic masses of A and B respectively, ara)120,212b)96,28c)212,120d)28,46Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Two elements A and B form compounds AB2 and AB4 (both are non-volatile and non-electrolyte) when dissolved in 20.0 g benzene, 1 g of AB2 lowers the freezing point of benzene by 2.3 K, whereas 1.0 g of AB4 lowers it by 1.3 K [Kf (benzene) = 5.5 K mol-1 kg]. ; Thus, atomic masses of A and B respectively, ara)120,212b)96,28c)212,120d)28,46Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.