All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >   wo beaker are placed in a sealed flask. Beak... Start Learning for Free
SaveJoin the Discussion on the App
wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.
The molar mass of solute in solution B is closest to:
  • a)
    60
  • b)
    30
  • c)
    181
  • d)
    342
Correct answer is option 'C'. Can you explain this answer?
FREE This question is part of
Download PDF Attempt Test
Download PDF Attempt this Test
Most Upvoted Answer
wo beaker are placed in a sealed flask. Beaker A initially contained ...
(m = moles of unknown solute)
Free Test
FREE
Start Free Test
Start Free Test
Community Answer
wo beaker are placed in a sealed flask. Beaker A initially contained ...
To solve this problem, we need to apply the concept of colligative properties and Raoult's law.

1. Understanding the concept of colligative properties:
Colligative properties are properties of a solution that depend on the number of solute particles, rather than the nature of the particles themselves. These properties include vapor pressure lowering, boiling point elevation, freezing point depression, and osmotic pressure.

2. Applying Raoult's law:
Raoult's law states that the vapor pressure of a solvent above a solution is directly proportional to the mole fraction of the solvent present in the solution.

3. Analyzing the given information:
Beaker A initially contained 0.15 mol of naphthalene in 117 g of benzene. Since naphthalene is non-volatile, it does not contribute to the vapor pressure of the solution. Therefore, the vapor pressure of the solution is solely determined by the benzene.

Beaker B initially contained 31 g of an unknown compound in 117 g of benzene. The unknown compound is also non-volatile, so it does not contribute to the vapor pressure of the solution. Again, the vapor pressure of the solution is solely determined by the benzene.

4. Understanding the weight loss in beaker A:
At equilibrium, beaker A is found to have lost 7.8 g of weight. This weight loss can be attributed to the evaporation of benzene from the solution. As a result, the mole fraction of benzene in the solution decreases, leading to a decrease in its vapor pressure.

5. Calculating the mole fraction of benzene in beaker A:
To calculate the mole fraction of benzene in beaker A, we need to determine the moles of benzene present in the initial solution and the moles of benzene remaining in the solution after the weight loss.

The initial moles of benzene can be calculated using its molar mass:
Molar mass of benzene (C6H6) = 12.01 g/mol (carbon) + 1.01 g/mol (hydrogen) * 6 = 78.11 g/mol

Moles of benzene in beaker A = 117 g / 78.11 g/mol = 1.5 mol

The remaining moles of benzene can be calculated by subtracting the moles of naphthalene lost from the initial moles of benzene:
Remaining moles of benzene = 1.5 mol - 0.15 mol = 1.35 mol

Now, we can calculate the mole fraction of benzene in beaker A:
Mole fraction of benzene = Moles of benzene / Total moles of solute and solvent
Mole fraction of benzene = 1.35 mol / (0.15 mol + 1.35 mol) = 0.9

6. Applying Raoult's law to beaker B:
Since beaker B initially contained the unknown compound and benzene, and both are non-volatile, their mole fractions in the solution remain the same. Therefore, the mole fraction of benzene in beaker B is also 0.9.

7. Using Raoult's law to calculate the vapor pressure of benzene in beaker B:
According to Raoult's law, the vapor pressure of benzene above the solution is directly proportional to its mole fraction.

< Previous Question Next Question >
Explore Courses for JEE exam

Similar JEE Doubts

A fuel cell is a cell that is continuously supplied with an oxidant and a reductant so that it can deliver a current indefinitely.Fuel cells offer the possibility of achieving high thermodynamic efficiency in the conversion of Gibbs energy into mechanical work. Internal combustion engines at best convert only the fraction (T2 T1)/T2 of the heat of combustion into mechanical work.While the thermodynamic efficiency of the fuel cell is given by, is theGibbs energy change for the cell reaction and H is the enthalpy change of the cell reaction.A hydrogen-oxygen fuel cell may have an acidic or alkaline electrolyte.Pt|H2(g)|H+(aq.)||H2O( l )|O2(g)|Pt; The above fuel cell is used to produce constant current supply under constant temperature 30 atm constant total pressure condition in a cylinder. If 10 moles H2 and 5 moles of O2 were taken initially. Rate of combustion of O2 is 10 milli moles per minute. The half cell reactions areTo maximize the power per unit mass of an electrochemical cell, the electronic and electrolytic resistances of the cell must be minimized. Since fused salts have lower electrolytic resistances than aqueous solutions, high-temperature electrochemical cells are of special interest for practical applications.Q.The above fuel cell is used completely as an electrolytic cell with Cu voltameter of resistance 26.94 W using Pt electrodes. Initially Cu voltameter contains 1 litre solution of 0.05M CuSO4.[H+] in solution after electrolysis (Assuming no change on volume of solution).

Top Courses for JEEView all

Top Courses for JEE

wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer?
Question Description
wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer?.
Solutions for wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer?, a detailed solution for wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice wo beaker are placed in a sealed flask. Beaker A initially contained 0.15 mol of naphthalene (non-volatile) in 117 g of benzene and beaker B initially contained 31 g of an unknown compound (non-volatile, non-electrolytic) in 117 g of benzene. At equilibrium, beaker A is found to have lost 7.8 g of weight. Assume ideal behaviour of both solutions to answer the following question.The molar mass of solute in solution B is closest to:a)60b)30c)181d)342Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup