**Product of the reaction between 1, 3-dibutene and bromoethane**

The reaction between 1,3-dibutene and bromoethane is an example of an electrophilic addition reaction, specifically an addition reaction between an alkene and a halogen. The reaction proceeds through the attack of the electrophilic bromine atom on the double bond of the alkene, followed by the formation of a new carbon-bromine bond.

**Reaction Mechanism**
1. The bromine atom in bromoethane acts as an electrophile and attacks the double bond of 1,3-dibutene. This results in the formation of a cyclic bromonium ion intermediate.
2. The cyclic bromonium ion is then attacked by a nucleophile, which can be either bromide ion or the double bond itself. In this case, the nucleophile is the double bond of 1,3-dibutene.
3. The attack of the nucleophile on the cyclic bromonium ion leads to the formation of a new carbon-carbon bond and a new carbon-bromine bond. This results in the formation of a five-membered cyclic alkyl bromide.

**Product Identification**
In the reaction between 1,3-dibutene and bromoethane, the cyclic alkyl bromide formed will have a five-membered ring, since 1,3-dibutene has four carbon atoms in its chain.

The product will have a bromine atom attached to one of the carbon atoms of the five-membered ring. Since the bromine atom in bromoethane is not a chiral center, the product will not have any stereoisomers.

**Identification of the Correct Product**
The correct product is identified as 4-bromocyclohexene, which corresponds to option A. This is because the cyclic alkyl bromide formed will have a six-membered ring, not a five-membered ring as observed in the reaction. Therefore, option A is incorrect.

**Conclusion**
The correct product of the reaction between 1,3-dibutene and bromoethane is not 4-bromocyclohexene, as mentioned in option A. The correct product is a five-membered cyclic alkyl bromide. The specific structure of the product will depend on the exact positioning of the bromine atom in the five-membered ring.