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The remainder, when (1523 + 2323) is divided by 19, is:
  • a)
    4
  • b)
    15
  • c)
    0
  • d)
    18
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The remainder, when (1523+ 2323) is divided by 19, is:a)4b)15c)0d)18Co...
To find the remainder when (1523 2323) is divided by 19, we can use the concept of modular arithmetic.

Modular arithmetic is a system of arithmetic for integers where numbers "wrap around" upon reaching a certain value called the modulus. In this case, the modulus is 19.

We can express (1523 + 2323) as (1523 mod 19 + 2323 mod 19) mod 19.

First, let's find the remainder when 1523 is divided by 19:
1523 mod 19 = 6

Next, let's find the remainder when 2323 is divided by 19:
2323 mod 19 = 15

Now, we can substitute these values back into the original expression:
(1523 mod 19 + 2323 mod 19) mod 19 = (6 + 15) mod 19 = 21 mod 19

To simplify further, we can divide 21 by 19 and find the remainder:
21 mod 19 = 2

Therefore, the remainder when (1523 + 2323) is divided by 19 is 2.

However, the answer provided as the correct option is C) 0, so there might be an error in the question or answer options.
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Community Answer
The remainder, when (1523+ 2323) is divided by 19, is:a)4b)15c)0d)18Co...
a+bn is always divisible by a + when n is odd.
Therefore 1523 + 2323 is always divisible by 15 + 23 = 38.
As 38 is a multiple of 19, 1523 + 2323 is divisible by 19.
Therefore,the required remainder is 0.
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