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At t=0 unit pulse voltage of unit width is applied to series RL circuit with R=1 ohm, L=1 find expression for current i(t)?
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At t=0 unit pulse voltage of unit width is applied to series RL circui...
Introduction
In this problem, we are given a series RL circuit with R=1 ohm, L=1, and a unit pulse voltage of unit width is applied at t=0. We have to find the expression for current i(t) in this circuit.
Step 1: Finding the Time Constant (τ)
The time constant (τ) of an RL circuit is given by the formula τ=L/R. In our circuit, R=1 ohm and L=1, so the time constant (τ) is equal to 1/1=1 second.
Step 2: Writing the Expression for Current (i(t))
The expression for current in an RL circuit with a unit step input is given by the formula i(t)=Ie^(-t/τ), where I is the amplitude of the step input and τ is the time constant of the circuit.
In our circuit, the step input is a unit pulse voltage of unit width, which means I=1. Therefore, the expression for current (i(t)) in our circuit is given by:
i(t)=e^(-t/τ)
Substituting the value of τ=1 second in the above expression, we get:
i(t)=e^(-t)
Therefore, the expression for current (i(t)) in our circuit is i(t)=e^(-t).
Conclusion
In conclusion, we have found the expression for current (i(t)) in a series RL circuit with R=1 ohm, L=1, and a unit pulse voltage of unit width is applied at t=0. The expression is i(t)=e^(-t).
In this problem, we are given a series RL circuit with R=1 ohm, L=1, and a unit pulse voltage of unit width is applied at t=0. We have to find the expression for current i(t) in this circuit.
Step 1: Finding the Time Constant (τ)
The time constant (τ) of an RL circuit is given by the formula τ=L/R. In our circuit, R=1 ohm and L=1, so the time constant (τ) is equal to 1/1=1 second.
Step 2: Writing the Expression for Current (i(t))
The expression for current in an RL circuit with a unit step input is given by the formula i(t)=Ie^(-t/τ), where I is the amplitude of the step input and τ is the time constant of the circuit.
In our circuit, the step input is a unit pulse voltage of unit width, which means I=1. Therefore, the expression for current (i(t)) in our circuit is given by:
i(t)=e^(-t/τ)
Substituting the value of τ=1 second in the above expression, we get:
i(t)=e^(-t)
Therefore, the expression for current (i(t)) in our circuit is i(t)=e^(-t).
Conclusion
In conclusion, we have found the expression for current (i(t)) in a series RL circuit with R=1 ohm, L=1, and a unit pulse voltage of unit width is applied at t=0. The expression is i(t)=e^(-t).
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At t=0 unit pulse voltage of unit width is applied to series RL circuit with R=1 ohm, L=1 find expression for current i(t)?
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At t=0 unit pulse voltage of unit width is applied to series RL circuit with R=1 ohm, L=1 find expression for current i(t)? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about At t=0 unit pulse voltage of unit width is applied to series RL circuit with R=1 ohm, L=1 find expression for current i(t)? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At t=0 unit pulse voltage of unit width is applied to series RL circuit with R=1 ohm, L=1 find expression for current i(t)?.
At t=0 unit pulse voltage of unit width is applied to series RL circuit with R=1 ohm, L=1 find expression for current i(t)? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about At t=0 unit pulse voltage of unit width is applied to series RL circuit with R=1 ohm, L=1 find expression for current i(t)? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At t=0 unit pulse voltage of unit width is applied to series RL circuit with R=1 ohm, L=1 find expression for current i(t)?.
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