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If S is a set of real numbers which is bounded above, then Sup S is
  • a)
    a point of closure to S
  • b)
    not a point of closure to S
  • c)
    prime number
  • d)
    None of the above
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If S is a set of real numbers which is bounded above, then Sup S isa)a...
Explanation:

To understand why option A is the correct answer, let's first define the terms involved in the question.

Definition of a bounded set:
A set of real numbers S is said to be bounded above if there exists a real number M such that every element in S is less than or equal to M. In other words, there is an upper bound on the set S.

Definition of the supremum:
The supremum of a set S, denoted as Sup S, is the least upper bound of the set S. It is the smallest real number M such that every element in S is less than or equal to M.

Now, let's consider the given options one by one:

Option A: Sup S is a point of closure to S
This option is correct. The supremum of a set S is a point of closure to S because it is the smallest real number that is greater than or equal to all the elements in S. In other words, it is a point that is close to all the elements in S.

Option B: Sup S is not a point of closure to S
This option is incorrect. As explained above, the supremum of a set S is a point of closure to S.

Option C: Prime number
This option is incorrect. The supremum of a set of real numbers has nothing to do with prime numbers. It is a concept related to the bounds of a set.

Option D: None of the above
This option is incorrect. Option A is the correct answer.

Conclusion:
The supremum of a bounded set of real numbers is a point of closure to the set. It is the smallest real number that is greater than or equal to all the elements in the set.
Free Test
Community Answer
If S is a set of real numbers which is bounded above, then Sup S isa)a...
Bcas,SupS is set of all upper bound .
so it has limit points
therefore it is closed.
a smallest closed set containing S. is called closure of S
so option A is right
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If S is a set of real numbers which is bounded above, then Sup S isa)a point of closure to Sb)not a point of closure to Sc)prime numberd)None of the aboveCorrect answer is option 'A'. Can you explain this answer?
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