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In the complex field c is the given vector space over the real field. R and operator T on C is defined as T(z)=z( bar) .then the matrix of T w.r.t. the basis {1 I,1 2i} is Ans in matrix please?
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In the complex field c is the given vector space over the real field. ...
Matrix of Operator T w.r.t. the Basis {1 I, 1 2i}

Definition of Operator T
The operator T on C is defined as T(z) = z(bar), where z(bar) is the complex conjugate of z.

Basis of Vector Space C
The basis of vector space C over the real field R is {1, i}.

Coordinate Vectors of Basis
The coordinate vectors of the basis {1, i} w.r.t. the basis {1, i} are [1 0] and [0 1], respectively.

Extension of Basis to {1 I, 1 2i}
To extend the basis to {1 I, 1 2i}, we need to express 1 and i in terms of 1 I and 1 2i.

Expressing 1 and i in terms of 1 I and 1 2i
1 = (1/3)(3) = (1/3)(1 I + 2i(1 2i)) and i = (1/3)(3i) = (1/3)(1 I - 2i(1 2i)).

Coordinate Vectors of Basis w.r.t. {1 I, 1 2i}
The coordinate vectors of the basis {1 I, 1 2i} w.r.t. the basis {1 I, 1 2i} are [1 0] and [0 1], respectively.

Matrix of Operator T w.r.t. {1 I, 1 2i}
To find the matrix of operator T w.r.t. the basis {1 I, 1 2i}, we need to apply T to each basis vector and write the result in terms of the basis {1 I, 1 2i}.

T(1) = 1(bar) = 1, so [T(1)] = [1 0].
T(I) = I(bar) = 1 - i(1 2i) = 1 - i + 2, so [T(I)] = [-i+3 2].

Therefore, the matrix of operator T w.r.t. the basis {1 I, 1 2i} is

[1 0]
[-i+3 2].
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In the complex field c is the given vector space over the real field. R and operator T on C is defined as T(z)=z( bar) .then the matrix of T w.r.t. the basis {1 I,1 2i} is Ans in matrix please?
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