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In a circle of radius 8 cm, AB and AC are two chords such that AB = AC = 12 cm. What is the length of chord BC?
- a)
- b)
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
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In a circle of radius 8 cm, AB and AC are two chords such that AB = AC...
O is the center of circle
Here ABC forms an isosceles triangle as AB=AC=12cm
So AE (a perpendicular bisector) passes through O as OE also bisects chord BC at right angle
AD = DB = 6
In triangle ADO
AO2 = AD2 + DO2
OD = √64 – 36 = √28
Now using similarity AEB~ADO
AB/AO = EB/DO
12/8 = (BC/2)/ √28
BC=6√7
Most Upvoted Answer
In a circle of radius 8 cm, AB and AC are two chords such that AB = AC...
O is the center of circle
Here ABC forms an isosceles triangle as AB=AC=12cm
So AE (a perpendicular bisector) passes through O as OE also bisects chord BC at right angle
AD = DB = 6
In triangle ADO
AO2 = AD2 + DO2
OD = √64 – 36 = √28
Now using similarity AEB~ADO
AB/AO = EB/DO
12/8 = (BC/2)/ √28
BC=6√7
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Community Answer
In a circle of radius 8 cm, AB and AC are two chords such that AB = AC...
O is the center of circle
Here ABC forms an isosceles triangle as AB=AC=12cm
So AE (a perpendicular bisector) passes through O as OE also bisects chord BC at right angle
AD = DB = 6
In triangle ADO
AO2 = AD2 + DO2
OD = √64 – 36 = √28
Now using similarity AEB~ADO
AB/AO = EB/DO
12/8 = (BC/2)/ √28
BC=6√7
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In a circle of radius 8 cm, AB and AC are two chords such that AB = AC = 12 cm. What is the length of chord BC?a)b)c)d)Correct answer is option 'D'. Can you explain this answer?
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