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DIRECTIONS for the question: Solve the following question and mark the best possible option.
A property dealer bought a rectangular piece of land at Rs. 1000/sq ft. The length of the plot is less than twice its breadth. Due to its size, there were no buyers for the full plot. Hence he decided to sell it in smaller sized pieces as given below:
The largest square from one end was sold at Rs. 1200/sqft. From the remaining rectangle the largest square was sold at Rs. 1150/sqft.
Due to crash in the property prices, the dealer found it difficult to make profit from the sale of the remaining part of the land. If the ratio of the perimeter of the remaining land to the perimeter of the original land is 3:8, at what price (in Rs.) the remaining part of the land is to be sold such that the dealer makes an overall profit of 10%?
  • a)
    500/sqft
  • b)
    550/sqft
  • c)
    600/sqft
  • d)
    650/sqft
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
DIRECTIONSfor the question:Solve the following question and mark the b...
This question can be done by reverse approach. As perimeter of remaining land (i.e. land left after selling two square plots) to original is 3:8. So we took the dimensions of smallest plot as 2 and 1 i.e. AD as 2 and AB as 1. As remaining plots are square, so remaining dimensions become as shown in figure. Also the Ratio of perimeter of Remaining plot to original plot becomes 6:16 i.e. 3:8. So Now we can solve the SP per sq ft. of remaining plot. 
     ► Total Area of plot = 3 × 5 = 15 sq. feet
     ► So cost @1000 per sq. feet = 15 × 1000 = Rs. 15000
     ► Since Profit = 10%
So total SP of entire plot = 15000 × 1.1 = Rs. 16500
     ► ∴ 16500 = 9 × 1200 +  4 × 1150 + 2.y
Where y is SP/sq. ft of remaining plot.
On solving we get y = Rs. 550.
Hence, option B is correct.
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Most Upvoted Answer
DIRECTIONSfor the question:Solve the following question and mark the b...
Given information:
- The property dealer bought a rectangular piece of land at Rs. 1000/sq ft.
- The length of the plot is less than twice its breadth.
- The largest square from one end was sold at Rs. 1200/sqft.
- From the remaining rectangle, the largest square was sold at Rs. 1150/sqft.
- The ratio of the perimeter of the remaining land to the perimeter of the original land is 3:8.
- The dealer wants to make an overall profit of 10%.

Approach:
1. Let's assume the breadth of the rectangular plot is 'b'. Therefore, the length of the plot is less than 2b.
2. We need to find the dimensions of the remaining part of the land and the price at which it should be sold to make a profit of 10%.
3. We will use the given information to form equations and solve them to find the required values.

Solution:

Step 1: Finding the dimensions of the rectangular plot
Let's assume the breadth of the plot is 'b'.
According to the given information, the length of the plot is less than twice its breadth.
So, the length (L) can be expressed as L < />

Step 2: Calculating the area of the largest square sold at Rs. 1200/sqft
The largest square is sold from one end of the plot. Let's assume its side length is 'x'.
So, the area of the largest square = x^2.

According to the given information, the area of the largest square sold at Rs. 1200/sqft = x^2.
Therefore, the cost of the largest square = x^2 * 1200.

Step 3: Calculating the area of the remaining rectangle after selling the largest square
The remaining rectangle has dimensions (L - x) and b.
So, the area of the remaining rectangle = (L - x) * b.

According to the given information, the area of the remaining rectangle = (L - x) * b.
Therefore, the cost of the remaining rectangle = (L - x) * b * 1000.

Step 4: Calculating the area of the largest square sold at Rs. 1150/sqft from the remaining rectangle
Let's assume the side length of the largest square sold from the remaining rectangle is 'y'.
So, the area of the largest square sold at Rs. 1150/sqft = y^2.

According to the given information, the area of the largest square sold at Rs. 1150/sqft = y^2.
Therefore, the cost of the largest square = y^2 * 1150.

Step 5: Forming equations using the given information
- The ratio of the perimeter of the remaining land to the perimeter of the original land is 3:8.
- The dealer wants to make an overall profit of 10%.

Let's assume the perimeter of the original land is 'P' and the perimeter of the remaining land is 'Q'.
So, according to the given information, Q/P = 3/8.

The dealer wants to make an overall profit of 10%. So, the total cost
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DIRECTIONSfor the question:Solve the following question and mark the best possible option.A property dealer bought a rectangular piece of land at Rs. 1000/sq ft.The length of the plot is less than twice its breadth. Due to its size, there were no buyers for the full plot. Hence he decided to sell it in smaller sized pieces as given below:The largest square from one end was sold at Rs. 1200/sqft. From the remaining rectangle the largest square was sold at Rs. 1150/sqft.Due to crash in the property prices, the dealer found it difficult to make profit from the sale of the remaining part of the land. If the ratio of the perimeter of the remaining land to the perimeter of the original land is 3:8, at what price (in Rs.) the remaining part of the land is to be sold such that the dealer makes an overall profit of 10%?a)500/sqftb)550/sqftc)600/sqftd)650/sqfte)None of theseCorrect answer is option 'B'. Can you explain this answer?
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DIRECTIONSfor the question:Solve the following question and mark the best possible option.A property dealer bought a rectangular piece of land at Rs. 1000/sq ft.The length of the plot is less than twice its breadth. Due to its size, there were no buyers for the full plot. Hence he decided to sell it in smaller sized pieces as given below:The largest square from one end was sold at Rs. 1200/sqft. From the remaining rectangle the largest square was sold at Rs. 1150/sqft.Due to crash in the property prices, the dealer found it difficult to make profit from the sale of the remaining part of the land. If the ratio of the perimeter of the remaining land to the perimeter of the original land is 3:8, at what price (in Rs.) the remaining part of the land is to be sold such that the dealer makes an overall profit of 10%?a)500/sqftb)550/sqftc)600/sqftd)650/sqfte)None of theseCorrect answer is option 'B'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about DIRECTIONSfor the question:Solve the following question and mark the best possible option.A property dealer bought a rectangular piece of land at Rs. 1000/sq ft.The length of the plot is less than twice its breadth. Due to its size, there were no buyers for the full plot. Hence he decided to sell it in smaller sized pieces as given below:The largest square from one end was sold at Rs. 1200/sqft. From the remaining rectangle the largest square was sold at Rs. 1150/sqft.Due to crash in the property prices, the dealer found it difficult to make profit from the sale of the remaining part of the land. If the ratio of the perimeter of the remaining land to the perimeter of the original land is 3:8, at what price (in Rs.) the remaining part of the land is to be sold such that the dealer makes an overall profit of 10%?a)500/sqftb)550/sqftc)600/sqftd)650/sqfte)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for DIRECTIONSfor the question:Solve the following question and mark the best possible option.A property dealer bought a rectangular piece of land at Rs. 1000/sq ft.The length of the plot is less than twice its breadth. Due to its size, there were no buyers for the full plot. Hence he decided to sell it in smaller sized pieces as given below:The largest square from one end was sold at Rs. 1200/sqft. From the remaining rectangle the largest square was sold at Rs. 1150/sqft.Due to crash in the property prices, the dealer found it difficult to make profit from the sale of the remaining part of the land. If the ratio of the perimeter of the remaining land to the perimeter of the original land is 3:8, at what price (in Rs.) the remaining part of the land is to be sold such that the dealer makes an overall profit of 10%?a)500/sqftb)550/sqftc)600/sqftd)650/sqfte)None of theseCorrect answer is option 'B'. Can you explain this answer?.
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