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A 30 mm hole shaft assembly results in minimum and maximum clearances of 0.03 mm and 0.30 mm respectively. The hole has a unilateral tolerance with zero fundamental deviation. If the tolerance on the shaft is 0.08 mm, the maximum size of the hole is
[PI 1992]
  • a)
    230.11
  • b)
    30.16
  • c)
    30.19
  • d)
    30.27
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A 30 mm hole shaft assembly results in minimum and maximum clearances ...
Min. clearance
= Holemin – Shaftmax = 0.03        ...(i)
Max clearance
= Holemin - Shaftmax = 0.30          ...(ii)
Shaftmax - Shaftmin = 0.08            ...(iii)
Since, hole has unilateral tolerance,
Hmin = 30 mm
From eq. (i), we get
Shaftmax = 30 - 0.03 = 29.97 min
From eq. (iii), we get
Shaftmin = 29.89 mm
From eq. (ii), we get
Holemax = 30.19 mm
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Most Upvoted Answer
A 30 mm hole shaft assembly results in minimum and maximum clearances ...
Min. clearance
= Holemin – Shaftmax = 0.03        ...(i)
Max clearance
= Holemin - Shaftmax = 0.30          ...(ii)
Shaftmax - Shaftmin = 0.08            ...(iii)
Since, hole has unilateral tolerance,
Hmin = 30 mm
From eq. (i), we get
Shaftmax = 30 - 0.03 = 29.97 min
From eq. (iii), we get
Shaftmin = 29.89 mm
From eq. (ii), we get
Holemax = 30.19 mm
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Community Answer
A 30 mm hole shaft assembly results in minimum and maximum clearances ...
To find the maximum size of the hole in the given 30 mm hole shaft assembly, we need to consider the unilateral tolerance on the shaft and the minimum and maximum clearances.

Given data:
Hole size = 30 mm
Minimum clearance = 0.03 mm
Maximum clearance = 0.30 mm
Tolerance on the shaft = 0.08 mm

To find the maximum size of the hole, we need to subtract the tolerance on the shaft from the minimum clearance. This is because the minimum clearance is the difference between the hole size and the maximum size of the shaft, and we need to find the maximum size of the hole.

Let's calculate the maximum size of the hole using the given data:

1. Find the maximum size of the shaft:
Maximum size of the shaft = Hole size - Minimum clearance
= 30 mm - 0.03 mm
= 29.97 mm

2. Find the maximum size of the hole:
Maximum size of the hole = Maximum size of the shaft - Tolerance on the shaft
= 29.97 mm - 0.08 mm
= 29.89 mm

Therefore, the maximum size of the hole in the given assembly is 29.89 mm. However, the options provided do not match this value.

It appears that there might be an error in the question or the options provided. Please double-check the given data and options to ensure accuracy.

Note: The correct answer should be within the range of the minimum and maximum clearances, which are 0.03 mm and 0.30 mm, respectively.
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A 30 mm hole shaft assembly results in minimum and maximum clearances of 0.03 mm and 0.30 mm respectively. The hole has a unilateral tolerance with zero fundamental deviation. If the tolerance on the shaft is 0.08 mm, the maximum size of the hole is[PI 1992]a)230.11b)30.16c)30.19d)30.27Correct answer is option 'C'. Can you explain this answer?
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A 30 mm hole shaft assembly results in minimum and maximum clearances of 0.03 mm and 0.30 mm respectively. The hole has a unilateral tolerance with zero fundamental deviation. If the tolerance on the shaft is 0.08 mm, the maximum size of the hole is[PI 1992]a)230.11b)30.16c)30.19d)30.27Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A 30 mm hole shaft assembly results in minimum and maximum clearances of 0.03 mm and 0.30 mm respectively. The hole has a unilateral tolerance with zero fundamental deviation. If the tolerance on the shaft is 0.08 mm, the maximum size of the hole is[PI 1992]a)230.11b)30.16c)30.19d)30.27Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 30 mm hole shaft assembly results in minimum and maximum clearances of 0.03 mm and 0.30 mm respectively. The hole has a unilateral tolerance with zero fundamental deviation. If the tolerance on the shaft is 0.08 mm, the maximum size of the hole is[PI 1992]a)230.11b)30.16c)30.19d)30.27Correct answer is option 'C'. Can you explain this answer?.
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