A pipeline conveys 8.23 litre per second of water from an overhead tank to a building. The pipe is 2 km long and 0.15 m in diameter. It is desired to increase the discharge by 30% by installing another pipeline in parallel with this over half the length. Suggest a suitable diameter of the pipe to be installed. Is there any upper limit on discharge augmentation by this arrangement? (Take friction factor f = 0.03. )a) 0.16 m and Qmax = 0.021 m3/sb) 0.17 m and Qmax = 0.012 m3/sc) 0.16 m and Qmax = 0.012 m3/sd) 0.17 m and Qmax = 0.021 m3/sCorrect answer is option 'C'. Can you explain this answer?

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a)
0.16 m and Qmax = 0.021 m³/s
b)
0.17 m and Qmax = 0.012 m³/s
c)
0.16 m and Qmax = 0.012 m³/s
d)
0.17 m and Qmax = 0.021 m³/s

Correct answer is option 'C'. Can you explain this answer?

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A pipeline conveys 8.23 litre per second of water from an overhead ta...

The height H of the overhead tank above the building can be determined from the conditions with a single pipe.

d = 0.15 m

l = 2 km

f = 0.03

In the new plan as shown in figure h_f = 4.53 = h_fAB + h_fBC ⋯ ① again,

In this case, Q = 1.3 × 0.00833 = 0.0108 m³/s Then, from equation ③, we get

Q₁² = 0.00014 − (0.0108)²

which gives Q1 = 0.0048 m³/s From continuity,

Q2 = 0.0108 − 0.0048

= 0.006 m³/s

From equation ②, we have

?₂ = 0.1?? ?

It can be observed from equation ③ that

Q₁² = 0.00014 − Q₂

or Q₂ = 0.00014 − Q₂¹

Now, Q will be maximum when Q₁ will be minimum. For a physically possible situation, the minimum value of Q₁ will be zero. Therefore, the maximum value of Q will be

Q_max = √0.00014 = 0.0118 m³/s which is 41.6% more than the initial value. The case (Q₁ = 0, Q = 0.0118 m³/s) corresponds to a situation of an infinitely large branched pipe, i.e. d2 → ∞.

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A pipeline conveys 8.23 litre per second of water from an overhead ta...

The height H of the overhead tank above the building can be determined from the conditions with a single pipe.

d = 0.15 m

l = 2 km

f = 0.03

In the new plan as shown in figure h_f = 4.53 = h_fAB + h_fBC ⋯ ① again,

In this case, Q = 1.3 × 0.00833 = 0.0108 m³/s Then, from equation ③, we get

Q₁² = 0.00014 − (0.0108)²

which gives Q1 = 0.0048 m³/s From continuity,

Q2 = 0.0108 − 0.0048

= 0.006 m³/s

From equation ②, we have

?₂ = 0.1?? ?

It can be observed from equation ③ that

Q₁² = 0.00014 − Q₂

or Q₂ = 0.00014 − Q₂¹

Now, Q will be maximum when Q₁ will be minimum. For a physically possible situation, the minimum value of Q₁ will be zero. Therefore, the maximum value of Q will be

Q_max = √0.00014 = 0.0118 m³/s which is 41.6% more than the initial value. The case (Q₁ = 0, Q = 0.0118 m³/s) corresponds to a situation of an infinitely large branched pipe, i.e. d2 → ∞.

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A pipeline conveys 8.23 litre per second of water from an overhead ta...

The height H of the overhead tank above the building can be determined from the conditions with a single pipe.

d = 0.15 m

l = 2 km

f = 0.03

In the new plan as shown in figure h_f = 4.53 = h_fAB + h_fBC ⋯ ① again,

In this case, Q = 1.3 × 0.00833 = 0.0108 m³/s Then, from equation ③, we get

Q₁² = 0.00014 − (0.0108)²

which gives Q1 = 0.0048 m³/s From continuity,

Q2 = 0.0108 − 0.0048

= 0.006 m³/s

From equation ②, we have

?₂ = 0.1?? ?

It can be observed from equation ③ that

Q₁² = 0.00014 − Q₂

or Q₂ = 0.00014 − Q₂¹

Now, Q will be maximum when Q₁ will be minimum. For a physically possible situation, the minimum value of Q₁ will be zero. Therefore, the maximum value of Q will be

Q_max = √0.00014 = 0.0118 m³/s which is 41.6% more than the initial value. The case (Q₁ = 0, Q = 0.0118 m³/s) corresponds to a situation of an infinitely large branched pipe, i.e. d2 → ∞.

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A pipeline conveys 8.23 litre per second of water from an overhead tank to a building. The pipe is 2 km long and 0.15 m in diameter. It is desired to increase the discharge by 30% by installing another pipeline in parallel with this over half the length. Suggest a suitable diameter of the pipe to be installed. Is there any upper limit on discharge augmentation by this arrangement? (Take friction factor f = 0.03. )a) 0.16 m and Qmax = 0.021 m3/sb) 0.17 m and Qmax = 0.012 m3/sc) 0.16 m and Qmax = 0.012 m3/sd) 0.17 m and Qmax = 0.021 m3/sCorrect answer is option 'C'. Can you explain this answer?

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A pipeline conveys 8.23 litre per second of water from an overhead tank to a building. The pipe is 2 km long and 0.15 m in diameter. It is desired to increase the discharge by 30% by installing another pipeline in parallel with this over half the length. Suggest a suitable diameter of the pipe to be installed. Is there any upper limit on discharge augmentation by this arrangement? (Take friction factor f = 0.03. )a) 0.16 m and Qmax = 0.021 m3/sb) 0.17 m and Qmax = 0.012 m3/sc) 0.16 m and Qmax = 0.012 m3/sd) 0.17 m and Qmax = 0.021 m3/sCorrect answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A pipeline conveys 8.23 litre per second of water from an overhead tank to a building. The pipe is 2 km long and 0.15 m in diameter. It is desired to increase the discharge by 30% by installing another pipeline in parallel with this over half the length. Suggest a suitable diameter of the pipe to be installed. Is there any upper limit on discharge augmentation by this arrangement? (Take friction factor f = 0.03. )a) 0.16 m and Qmax = 0.021 m3/sb) 0.17 m and Qmax = 0.012 m3/sc) 0.16 m and Qmax = 0.012 m3/sd) 0.17 m and Qmax = 0.021 m3/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pipeline conveys 8.23 litre per second of water from an overhead tank to a building. The pipe is 2 km long and 0.15 m in diameter. It is desired to increase the discharge by 30% by installing another pipeline in parallel with this over half the length. Suggest a suitable diameter of the pipe to be installed. Is there any upper limit on discharge augmentation by this arrangement? (Take friction factor f = 0.03. )a) 0.16 m and Qmax = 0.021 m3/sb) 0.17 m and Qmax = 0.012 m3/sc) 0.16 m and Qmax = 0.012 m3/sd) 0.17 m and Qmax = 0.021 m3/sCorrect answer is option 'C'. Can you explain this answer?.

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