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The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2?
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Calculation of Frequency for Pure Rotational Spectrum of NO Molecule
The frequency for the pure rotational spectrum of a molecule can be calculated using the formula:
\[ \Delta E = B \times (J+1) - B \times J \]
where:
- \( \Delta E \) is the energy difference between two adjacent rotational levels
- B is the rotational constant of the molecule
- J is the quantum number representing the rotational level
Given Data:
- Change in quantum number, \( \Delta J = 2 - 1 = 1 \)
Calculation:
- Since \( \Delta E = B \times (J+1) - B \times J \), substituting \( \Delta J = 1 \) into the formula gives:
\[ \Delta E = B \times (1+1) - B \times 1 = B \]
- The frequency of the rotational transition can be calculated using the relation:
\[ \Delta E = h \times \nu \]
where:
- h is the Planck's constant
- \( \nu \) is the frequency
- Equating the two equations gives:
\[ B = h \times \nu \]
\[ \nu = \frac{B}{h} \]
- Finally, substituting the rotational constant for NO molecule and Planck's constant into the formula gives the frequency in cm\(^{-1}\).
Therefore, the frequency for the pure rotational spectrum in cm\(^{-1}\) due to the change in the quantum number from J=1 to J=2 for the NO molecule can be calculated using the above steps.
The frequency for the pure rotational spectrum of a molecule can be calculated using the formula:
\[ \Delta E = B \times (J+1) - B \times J \]
where:
- \( \Delta E \) is the energy difference between two adjacent rotational levels
- B is the rotational constant of the molecule
- J is the quantum number representing the rotational level
Given Data:
- Change in quantum number, \( \Delta J = 2 - 1 = 1 \)
Calculation:
- Since \( \Delta E = B \times (J+1) - B \times J \), substituting \( \Delta J = 1 \) into the formula gives:
\[ \Delta E = B \times (1+1) - B \times 1 = B \]
- The frequency of the rotational transition can be calculated using the relation:
\[ \Delta E = h \times \nu \]
where:
- h is the Planck's constant
- \( \nu \) is the frequency
- Equating the two equations gives:
\[ B = h \times \nu \]
\[ \nu = \frac{B}{h} \]
- Finally, substituting the rotational constant for NO molecule and Planck's constant into the formula gives the frequency in cm\(^{-1}\).
Therefore, the frequency for the pure rotational spectrum in cm\(^{-1}\) due to the change in the quantum number from J=1 to J=2 for the NO molecule can be calculated using the above steps.
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The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2?
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The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2?.
The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2?.
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