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A container full of oil has a horizontal parallel crack in its end wall which is 500 mm wide and 50 mm thick in the direction of flow. The pressure difference between two faces of the crack is 10 kPa and the crack forms a gap of 0.4 mm between the parallel surfaces.
Calculate
(i) Maximum leakage velocity;
(ii) Shear stress at the boundary.
Take specific gravity and viscosity of oil equal to 0.85 and 1.8 poise respectively.
  • a)
    0.022 m/s ; 40 N/m2
  • b)
    0.22 m/s ; 0.4 N/m2
  • c)
    2.2 m/s ; 0.04 N/m2
  • d)
    2.2 m/s ; 40 N/m2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A container full of oil has a horizontal parallel crack in its end wa...
Μ = 1.8 poise = 1.8 × 0.1 = 0.18 Ns⁄m2
b = 0.4 mm = 0.0004 m
l = 50 mm = 0.05 m
p1 − p2 = 10 kPa = 10 × 103 N⁄m2
(i) The oil leakage through the crack corresponds to the case of flow between two stationary parallel surfaces for which
(ii) The maximum velocity occurs midway between the crack
Shear stress at the wall,
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Most Upvoted Answer
A container full of oil has a horizontal parallel crack in its end wa...
Μ = 1.8 poise = 1.8 × 0.1 = 0.18 Ns⁄m2
b = 0.4 mm = 0.0004 m
l = 50 mm = 0.05 m
p1 − p2 = 10 kPa = 10 × 103 N⁄m2
(i) The oil leakage through the crack corresponds to the case of flow between two stationary parallel surfaces for which
(ii) The maximum velocity occurs midway between the crack
Shear stress at the wall,
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Community Answer
A container full of oil has a horizontal parallel crack in its end wa...
Given Data:
- Width of the crack (b) = 500 mm = 0.5 m
- Thickness of the crack (h) = 50 mm = 0.05 m
- Pressure difference (ΔP) = 10 kPa = 10,000 N/m²
- Gap between the surfaces (δ) = 0.4 mm = 0.0004 m
- Specific gravity of oil (SG) = 0.85
- Viscosity of oil (μ) = 1.8 poise = 0.018 kg/(m·s)

(i) Maximum leakage velocity:
The maximum leakage velocity (V) can be determined using the equation:

V = (2 * ΔP * h) / (3 * μ * δ)

Substituting the given values:

V = (2 * 10,000 * 0.05) / (3 * 0.018 * 0.0004)
V = 0.022 m/s

Therefore, the maximum leakage velocity is 0.022 m/s.

(ii) Shear stress at the boundary:
The shear stress at the boundary (τ) can be calculated using the equation:

τ = (4 * μ * V) / (b * h)

Substituting the given values:

τ = (4 * 0.018 * 0.022) / (0.5 * 0.05)
τ = 40 N/m²

Therefore, the shear stress at the boundary is 40 N/m².

Hence, the correct answer is option 'A' (0.022 m/s; 40 N/m²).
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A container full of oil has a horizontal parallel crack in its end wall which is 500 mm wide and 50 mm thick in the direction of flow. The pressure difference between two faces of the crack is 10 kPa and the crack forms a gap of 0.4 mm between the parallel surfaces.Calculate(i) Maximum leakage velocity;(ii) Shear stress at the boundary.Take specific gravity and viscosity of oil equal to 0.85 and 1.8 poise respectively.a) 0.022 m/s ; 40 N/m2b) 0.22 m/s ; 0.4 N/m2c) 2.2 m/s ; 0.04 N/m2d) 2.2 m/s ; 40 N/m2Correct answer is option 'A'. Can you explain this answer?
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A container full of oil has a horizontal parallel crack in its end wall which is 500 mm wide and 50 mm thick in the direction of flow. The pressure difference between two faces of the crack is 10 kPa and the crack forms a gap of 0.4 mm between the parallel surfaces.Calculate(i) Maximum leakage velocity;(ii) Shear stress at the boundary.Take specific gravity and viscosity of oil equal to 0.85 and 1.8 poise respectively.a) 0.022 m/s ; 40 N/m2b) 0.22 m/s ; 0.4 N/m2c) 2.2 m/s ; 0.04 N/m2d) 2.2 m/s ; 40 N/m2Correct answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A container full of oil has a horizontal parallel crack in its end wall which is 500 mm wide and 50 mm thick in the direction of flow. The pressure difference between two faces of the crack is 10 kPa and the crack forms a gap of 0.4 mm between the parallel surfaces.Calculate(i) Maximum leakage velocity;(ii) Shear stress at the boundary.Take specific gravity and viscosity of oil equal to 0.85 and 1.8 poise respectively.a) 0.022 m/s ; 40 N/m2b) 0.22 m/s ; 0.4 N/m2c) 2.2 m/s ; 0.04 N/m2d) 2.2 m/s ; 40 N/m2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A container full of oil has a horizontal parallel crack in its end wall which is 500 mm wide and 50 mm thick in the direction of flow. The pressure difference between two faces of the crack is 10 kPa and the crack forms a gap of 0.4 mm between the parallel surfaces.Calculate(i) Maximum leakage velocity;(ii) Shear stress at the boundary.Take specific gravity and viscosity of oil equal to 0.85 and 1.8 poise respectively.a) 0.022 m/s ; 40 N/m2b) 0.22 m/s ; 0.4 N/m2c) 2.2 m/s ; 0.04 N/m2d) 2.2 m/s ; 40 N/m2Correct answer is option 'A'. Can you explain this answer?.
Solutions for A container full of oil has a horizontal parallel crack in its end wall which is 500 mm wide and 50 mm thick in the direction of flow. The pressure difference between two faces of the crack is 10 kPa and the crack forms a gap of 0.4 mm between the parallel surfaces.Calculate(i) Maximum leakage velocity;(ii) Shear stress at the boundary.Take specific gravity and viscosity of oil equal to 0.85 and 1.8 poise respectively.a) 0.022 m/s ; 40 N/m2b) 0.22 m/s ; 0.4 N/m2c) 2.2 m/s ; 0.04 N/m2d) 2.2 m/s ; 40 N/m2Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
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