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A singal phase transformer is rated at 100 kva at full load its copper losses are 1200 watt and iron losses are 960 watt calculate 1.afficiancy at half load and 0.8 power fector?
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A singal phase transformer is rated at 100 kva at full load its copper...
Calculation of Efficiency at Half Load and 0.8 Power Factor


Given Data:


  • Transformer Rating (kVA) = 100

  • Copper Losses (W) = 1200

  • Iron Losses (W) = 960



Efficiency Formula:

Efficiency = (Output Power / Input Power) x 100%

Calculation of Output Power:

Output Power = Transformer Rating x Load Power Factor x Load Fraction

At Half Load, Load Fraction = 0.5
At 0.8 Power Factor, Load Power Factor = 0.8

Output Power = 100 x 0.8 x 0.5 = 40 kW

Calculation of Input Power:

Input Power = Output Power + Copper Losses + Iron Losses

Input Power = 40,000 + 1200 + 960 = 42,160 W

Calculation of Efficiency:

Efficiency = (Output Power / Input Power) x 100%

Efficiency = (40,000 / 42,160) x 100% = 94.98%

Explanation:


  • Efficiency is the ratio of output power to input power.

  • At half load and 0.8 power factor, the output power is 40 kW.

  • The input power is calculated by adding the copper losses and iron losses to the output power.

  • The efficiency is then calculated using the formula and is found to be 94.98%.

  • This means that the transformer is able to convert 94.98% of the input power into output power.
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A singal phase transformer is rated at 100 kva at full load its copper losses are 1200 watt and iron losses are 960 watt calculate 1.afficiancy at half load and 0.8 power fector?
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