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Min z = 4x1 + 6x2
s/t: x1 + x2 ≤ 4
x1 + 2x2 ≥ 6
x1, x2 ≥ 0
The type of solution is
  • a)
    unique
  • b)
    unbounded
  • c)
    infeasible
  • d)
    multiple optimal
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Min z = 4x1 + 6x2s/t: x1 + x2 ≤ 4x1 + 2x2 ≥ 6x1, x2 ≥ 0The type of so...
Given,
x1 + x2 ≤ 4; (0, 4)(4, 0)
x1 + 2x2 ≥ 6; (0, 3)(6, 0)
only one point:
Z(0,0) = 0
Z(0,3) = 18
Z(2,2) = 20
Z(4,0) = 16
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Most Upvoted Answer
Min z = 4x1 + 6x2s/t: x1 + x2 ≤ 4x1 + 2x2 ≥ 6x1, x2 ≥ 0The type of so...
Given,
x1 + x2 ≤ 4; (0, 4)(4, 0)
x1 + 2x2 ≥ 6; (0, 3)(6, 0)
only one point:
Z(0,0) = 0
Z(0,3) = 18
Z(2,2) = 20
Z(4,0) = 16
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