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Let f(x) = (x – 2)17 (x + 5)24. Then
  • a)
    f has neither minimum nor a maximum at x = 2
  • b)
    f does not have a critical point at 2 
  • c)
    f has a minimum at 2 
  • d)
    f has a maximum at 2 
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Let f(x) = (x – 2)17 (x + 5)24. Thena)f has neither minimum nor ...
Here f (x) = (x – 2)17 (x + 5)24 
f17 (2) ≠ 0
⇒ Odd derivative of the function is non-zero.
So, f has neither a minimum nor a maximum at 2.
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Let f(x) = (x – 2)17 (x + 5)24. Thena)f has neither minimum nor ...
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Let f(x) = (x – 2)17 (x + 5)24. Thena)f has neither minimum nor a maximum at x = 2b)f does not have a critical point at 2c)f has a minimum at 2d)f has a maximum at 2Correct answer is option 'A'. Can you explain this answer?
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