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A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet is
- a)490.44 MJ
- b)30.95 MJ
- c)10.35 MJ
- d)0.10 MJ
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. T...
Heat lost by steel = (0.5)(2000)(450 – 1250)
Gained = 800MJ
ΔSLost by steel = (2000) (0.5)) ln
⇒ –1.021 MJ
(ΔS) gained = 1.021MJ
AE (W) = a – T0dS
= 800 – (303) (1.021)
= 490.7 MJ
Gained = 800MJ
ΔSLost by steel = (2000) (0.5)) ln
⇒ –1.021 MJ
(ΔS) gained = 1.021MJ
AE (W) = a – T0dS
= 800 – (303) (1.021)
= 490.7 MJ
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A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. T...
Given data:
- Mass of steel billet (m) = 2000 kg
- Initial temperature (T1) = 1250 K
- Final temperature (T2) = 450 K
- Ambient temperature (Ta) = 303 K
- Specific heat of steel (Cp) = 0.5 kJ/kgK
We need to calculate the available energy released during the cooling process.
The heat released during the cooling process can be calculated using the formula:
Q = mcΔT
Where:
Q = Heat released (in Joules)
m = Mass of the steel billet (in kg)
c = Specific heat of steel (in kJ/kgK)
ΔT = Change in temperature (T1 - T2) (in K)
Calculating the change in temperature:
ΔT = T1 - T2
ΔT = 1250 K - 450 K
ΔT = 800 K
Calculating the heat released:
Q = mcΔT
Q = 2000 kg * 0.5 kJ/kgK * 800 K
Q = 800,000 kJ
Converting kJ to MJ:
1 MJ = 1000 kJ
800,000 kJ = 800 MJ
Calculating the available energy:
The available energy is the heat released minus the heat absorbed by the surroundings (ambient temperature).
Heat absorbed by the surroundings (Qa) can be calculated using the formula:
Qa = mCpΔTa
Where:
Qa = Heat absorbed by the surroundings (in Joules)
m = Mass of the steel billet (in kg)
Cp = Specific heat of steel (in kJ/kgK)
ΔTa = Change in temperature (T1 - Ta) (in K)
Calculating the change in temperature:
ΔTa = T1 - Ta
ΔTa = 1250 K - 303 K
ΔTa = 947 K
Calculating the heat absorbed by the surroundings:
Qa = mCpΔTa
Qa = 2000 kg * 0.5 kJ/kgK * 947 K
Qa = 947,000 kJ
Converting kJ to MJ:
1 MJ = 1000 kJ
947,000 kJ = 947 MJ
Calculating the available energy:
Available energy = Heat released - Heat absorbed by the surroundings
Available energy = 800 MJ - 947 MJ
Available energy = -147 MJ
From the calculation, we can see that the available energy is negative, which means the heat absorbed by the surroundings is greater than the heat released. Therefore, the correct answer cannot be option 'A' (490.44 MJ).
There might be an error in the given options or data, as the available energy cannot be calculated based on the provided information.
- Mass of steel billet (m) = 2000 kg
- Initial temperature (T1) = 1250 K
- Final temperature (T2) = 450 K
- Ambient temperature (Ta) = 303 K
- Specific heat of steel (Cp) = 0.5 kJ/kgK
We need to calculate the available energy released during the cooling process.
The heat released during the cooling process can be calculated using the formula:
Q = mcΔT
Where:
Q = Heat released (in Joules)
m = Mass of the steel billet (in kg)
c = Specific heat of steel (in kJ/kgK)
ΔT = Change in temperature (T1 - T2) (in K)
Calculating the change in temperature:
ΔT = T1 - T2
ΔT = 1250 K - 450 K
ΔT = 800 K
Calculating the heat released:
Q = mcΔT
Q = 2000 kg * 0.5 kJ/kgK * 800 K
Q = 800,000 kJ
Converting kJ to MJ:
1 MJ = 1000 kJ
800,000 kJ = 800 MJ
Calculating the available energy:
The available energy is the heat released minus the heat absorbed by the surroundings (ambient temperature).
Heat absorbed by the surroundings (Qa) can be calculated using the formula:
Qa = mCpΔTa
Where:
Qa = Heat absorbed by the surroundings (in Joules)
m = Mass of the steel billet (in kg)
Cp = Specific heat of steel (in kJ/kgK)
ΔTa = Change in temperature (T1 - Ta) (in K)
Calculating the change in temperature:
ΔTa = T1 - Ta
ΔTa = 1250 K - 303 K
ΔTa = 947 K
Calculating the heat absorbed by the surroundings:
Qa = mCpΔTa
Qa = 2000 kg * 0.5 kJ/kgK * 947 K
Qa = 947,000 kJ
Converting kJ to MJ:
1 MJ = 1000 kJ
947,000 kJ = 947 MJ
Calculating the available energy:
Available energy = Heat released - Heat absorbed by the surroundings
Available energy = 800 MJ - 947 MJ
Available energy = -147 MJ
From the calculation, we can see that the available energy is negative, which means the heat absorbed by the surroundings is greater than the heat released. Therefore, the correct answer cannot be option 'A' (490.44 MJ).
There might be an error in the given options or data, as the available energy cannot be calculated based on the provided information.
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A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer?.
A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A steel billet of 2000 kg mass is to be cooled from 1250 K to 450 K. The heat released during this process is to be used as a source of energy. The ambient temperature is 303 K and specific heat of steel is 0.5 kJ/kgK. The available energy of this billet isa)490.44 MJb)30.95 MJc)10.35 MJd)0.10 MJCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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