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The pressure, temperature and velocity of air flowing in pipe are 5 bar, 500 K and 50 m/s, respectively. The specific heats of air at a constant pressure and at constant volume are 1.005 kJ/kgK and 0.718 kJ/kgK, respectively.Neglect potential energy. If the pressure and temperature of the surroundings are 1 bar and 300 K, respectively, the available energy in kJ/ kg of the air stream is
  • a)
    170
  • b)
    187
  • c)
    191
  • d)
    213
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The pressure, temperature and velocity of air flowing in pipe are 5 ba...
For flow stream,
A.E. =(h2 – h1) + K.E. – T0 (S2 – S1)

= 187 kJ/kg
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Most Upvoted Answer
The pressure, temperature and velocity of air flowing in pipe are 5 ba...


Given data:
- Pressure (P1) = 5 bar
- Temperature (T1) = 500 K
- Velocity (V) = 50 m/s
- Specific heat at constant pressure (Cp) = 1.005 kJ/kgK
- Specific heat at constant volume (Cv) = 0.718 kJ/kgK
- Pressure of surroundings (P0) = 1 bar
- Temperature of surroundings (T0) = 300 K

Step 1: Calculate the specific enthalpy of the air stream
The specific enthalpy (h) of the air stream can be calculated using the formula:
\[ h = Cp * T1 + 0.5 * V^2 \]

Substitute the given values:
\[ h = 1.005 * 500 + 0.5 * 50^2 = 502.5 + 1250 = 1752.5 kJ/kg \]

Step 2: Calculate the specific enthalpy of the air stream at the surroundings
The specific enthalpy of the air stream at the surroundings can be calculated using the formula:
\[ h0 = Cp * T0 \]

Substitute the given values:
\[ h0 = 1.005 * 300 = 301.5 kJ/kg \]

Step 3: Calculate the available energy
The available energy per unit mass of the air stream can be calculated using the formula:
\[ Available Energy = h - h0 \]

Substitute the calculated values:
\[ Available Energy = 1752.5 - 301.5 = 1451 kJ/kg \]

Therefore, the available energy in kJ/kg of the air stream is 1451 kJ/kg, which is closest to option B (187 kJ/kg).
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Community Answer
The pressure, temperature and velocity of air flowing in pipe are 5 ba...
For flow stream,
A.E. =(h2 – h1) + K.E. – T0 (S2 – S1)

= 187 kJ/kg
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The pressure, temperature and velocity of air flowing in pipe are 5 bar, 500 K and 50 m/s, respectively. The specific heats of air at a constant pressure and at constant volume are 1.005 kJ/kgK and 0.718 kJ/kgK, respectively.Neglect potential energy. If the pressure and temperature of the surroundings are 1 bar and 300 K, respectively, the available energy in kJ/ kg of the air stream isa)170b)187c)191d)213Correct answer is option 'B'. Can you explain this answer?
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