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If the moment of inertia of a section about its orthogonal axes are 1 × 106 and 2 × 106 and its area is 1000 units. Its polar moment of inertia is
  • a)
    3 × 106
  • b)
    5 × 106
  • c)
    4 × 106
  • d)
    3.1 × 10
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If the moment of inertia of a section about its orthogonal axes are 1...
Polar moment of inertia
Izz = Ixx + Iyy
= 1 × 106 + 2 × 106
Izz = 3 × 106
Free Test
Community Answer
If the moment of inertia of a section about its orthogonal axes are 1...
To find the polar moment of inertia of a section, we need to know the moment of inertia about its orthogonal axes. The polar moment of inertia represents the resistance of a section to torsion or twisting.

Given:
Moment of inertia about the x-axis (Ix) = 1 × 10^6
Moment of inertia about the y-axis (Iy) = 2 × 10^6
Area of the section (A) = 1000 units

Formula:
The polar moment of inertia (J) is given by the sum of the moments of inertia about the x and y axes.
J = Ix + Iy

Calculation:
Substituting the given values,
J = 1 × 10^6 + 2 × 10^6
J = 3 × 10^6

So, the polar moment of inertia (J) is 3 × 10^6. Therefore, the correct answer is option A) 3 × 10^6.
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