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The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa is
- a)157.1 GNm2
- b)637.8 GNm2
- c)341.1 GNm2
- d)314.1 GNm2
Correct answer is option 'B'. Can you explain this answer?
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The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm...
Torsional rigidity,
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GJ = 100 × 103 × 
= 637.8 × 109Nm2
= 637.8GNm2
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The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm...
Calculation of Torsional Rigidity of a Tube
Given parameters:
- Thickness (t) = 1.0 mm
- Diameter (d) = 200 mm
- Rigidity modulus (G) = 100.0 GPa
Formula:
- Torsional Rigidity (J) = (π/2) * G * t^4 / (1 - 0.25d^(-4))
Calculation:
- Substituting the given values in the formula, we get:
J = (π/2) * 100.0 * 10^9 * (0.001)^4 / (1 - 0.25 * (0.2)^(-4))
- Simplifying the expression, we get:
J = 637.8 GN-m^2
Therefore, the torsional rigidity of the tube is 637.8 GN-m^2, which is option B.
Given parameters:
- Thickness (t) = 1.0 mm
- Diameter (d) = 200 mm
- Rigidity modulus (G) = 100.0 GPa
Formula:
- Torsional Rigidity (J) = (π/2) * G * t^4 / (1 - 0.25d^(-4))
Calculation:
- Substituting the given values in the formula, we get:
J = (π/2) * 100.0 * 10^9 * (0.001)^4 / (1 - 0.25 * (0.2)^(-4))
- Simplifying the expression, we get:
J = 637.8 GN-m^2
Therefore, the torsional rigidity of the tube is 637.8 GN-m^2, which is option B.
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The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GNm2b) 637.8 GNm2c) 341.1 GNm2d) 314.1 GNm2Correct answer is option 'B'. Can you explain this answer?
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The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GNm2b) 637.8 GNm2c) 341.1 GNm2d) 314.1 GNm2Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GNm2b) 637.8 GNm2c) 341.1 GNm2d) 314.1 GNm2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GNm2b) 637.8 GNm2c) 341.1 GNm2d) 314.1 GNm2Correct answer is option 'B'. Can you explain this answer?.
The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GNm2b) 637.8 GNm2c) 341.1 GNm2d) 314.1 GNm2Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GNm2b) 637.8 GNm2c) 341.1 GNm2d) 314.1 GNm2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GNm2b) 637.8 GNm2c) 341.1 GNm2d) 314.1 GNm2Correct answer is option 'B'. Can you explain this answer?.
Solutions for The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GNm2b) 637.8 GNm2c) 341.1 GNm2d) 314.1 GNm2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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