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The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa is
  • a)
    157.1 GN­m2
  • b)
    637.8 GN­m2
  • c)
    341.1 GN­m2
  • d)
    314.1 GN­m2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm...
Torsional rigidity,
GJ = 100 × 103 ×
= 637.8 × 109N­m2
= 637.8GN­m2
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Most Upvoted Answer
The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm...
Calculation of Torsional Rigidity of a Tube

Given parameters:

- Thickness (t) = 1.0 mm
- Diameter (d) = 200 mm
- Rigidity modulus (G) = 100.0 GPa

Formula:

- Torsional Rigidity (J) = (π/2) * G * t^4 / (1 - 0.25d^(-4))

Calculation:

- Substituting the given values in the formula, we get:
J = (π/2) * 100.0 * 10^9 * (0.001)^4 / (1 - 0.25 * (0.2)^(-4))
- Simplifying the expression, we get:
J = 637.8 GN-m^2

Therefore, the torsional rigidity of the tube is 637.8 GN-m^2, which is option B.
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The torsional rigidity of a tube of thickness 1.0 mm, diameter 200 mm and rigidity modulus 100.0 GPa isa) 157.1 GN­m2b) 637.8 GN­m2c) 341.1 GN­m2d) 314.1 GN­m2Correct answer is option 'B'. Can you explain this answer?
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