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Suppose (cn) is a sequence of real numbers such that |cn|1/n exists and is non-zero. If the radius of convergence of the power series cn xn is equal to r, then the radius of convergence of the power series n2cnxn is
 
  • a)
    less than r
     
  • b)
    greater than r
  • c)
    equal to r
  • d)
    equal to 0
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Suppose (cn) is a sequence of real numbers such that |cn|1/n exists a...
Radius of convergence = R =
⇒ R = r
So radius of convergence of is
R1 = 
r.1 = 1
 
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Most Upvoted Answer
Suppose (cn) is a sequence of real numbers such that |cn|1/n exists a...
Radius of convergence = R =
⇒ R = r
So radius of convergence of is
R1 = 
r.1 = 1
 
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Suppose (cn) is a sequence of real numbers such that |cn|1/n exists and is non-zero. If the radius of convergence of the power series cn xn is equal to r, then the radius of convergence of the power series n2cnxn isa)less thanrb)greater than rc)equal to rd)equal to 0Correct answer is option 'C'. Can you explain this answer?
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Suppose (cn) is a sequence of real numbers such that |cn|1/n exists and is non-zero. If the radius of convergence of the power series cn xn is equal to r, then the radius of convergence of the power series n2cnxn isa)less thanrb)greater than rc)equal to rd)equal to 0Correct answer is option 'C'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about Suppose (cn) is a sequence of real numbers such that |cn|1/n exists and is non-zero. If the radius of convergence of the power series cn xn is equal to r, then the radius of convergence of the power series n2cnxn isa)less thanrb)greater than rc)equal to rd)equal to 0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose (cn) is a sequence of real numbers such that |cn|1/n exists and is non-zero. If the radius of convergence of the power series cn xn is equal to r, then the radius of convergence of the power series n2cnxn isa)less thanrb)greater than rc)equal to rd)equal to 0Correct answer is option 'C'. Can you explain this answer?.
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