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If the deflection at the free end of a uniformly loaded cantilever beam is 15 mm and the slope of the deflection curve at the free end is 0.02 radian. then the length of the beam is
  • a)
    0.8 m
  • b)
    1 m
  • c)
    1.2 m
  • d)
    1.5 m
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If the deflection at the free end of a uniformly loaded cantilever be...
Deflection at free end, δ = = 15 mm
Slope at free end, θ = = 0.02
∴ From the two
L = 1 m
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Community Answer
If the deflection at the free end of a uniformly loaded cantilever be...
Given data:
Deflection at free end, y = 15 mm
Slope of deflection curve at free end, θ = 0.02 radian

To find: Length of the beam

Formula used:
The deflection at the free end of a cantilever beam under a uniformly distributed load is given by:
y = (wL^3)/(3EI)

The slope of the deflection curve at the free end of a cantilever beam under a uniformly distributed load is given by:
θ = (wL^2)/(2EI)

where,
w = uniformly distributed load
L = length of the beam
E = Young's modulus of the material of the beam
I = moment of inertia of the beam cross-section

Calculation:
Let's assume the Young's modulus and moment of inertia are the same throughout the beam. Therefore, we can equate the above two formulas to get the value of wL.
y = (wL^3)/(3EI)
θ = (wL^2)/(2EI)

Combining the above two equations, we get:
θ = (2y/L) * (1/L)

Solving for L, we get:
L = (2y/θ)^0.5

Substituting the given values, we get:
L = (2*15/0.02)^0.5
L = 1224.74 mm or 1.2247 m

Therefore, the length of the beam is 1 m (approx).

Hence, option (b) is the correct answer.
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