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In the acid catalyzed dehydration of alcohols to alkenes, the intermediate species formed is
  • a)
    Free radical 
  • b)
    Carbocation
  • c)
    Carbanion 
  • d)
    Carbene
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In the acid catalyzed dehydration of alcohols to alkenes, the intermed...
Acid catalyzed dehydration of alcohols involves the removal of water molecule from an alcohol in the presence of an acid catalyst. This reaction proceeds through a carbocation intermediate, which is formed by protonation of the hydroxyl group of the alcohol.

Explanation:
• Acid catalyzed dehydration of alcohols involves the removal of water molecule from an alcohol in the presence of an acid catalyst.
• The reaction proceeds through a carbocation intermediate, which is formed by protonation of the hydroxyl group of the alcohol.
• The carbocation intermediate is stabilized by resonance, which helps to lower the energy of the intermediate species.
• After the carbocation is formed, a neighboring hydrogen is removed by a base (often water in the reaction mixture) to form an alkene.
• The mechanism of the reaction involves a series of proton transfer steps and bond breaking and forming steps, which ultimately lead to the formation of an alkene.
• The acid catalyst (such as sulfuric acid or phosphoric acid) helps to increase the acidity of the reaction mixture, which in turn facilitates the formation of the carbocation intermediate.
• The formation of the carbocation intermediate is the rate-determining step of the reaction, as it is the slowest step in the mechanism.
• Once the carbocation is formed, the reaction proceeds rapidly to form the alkene product.

Conclusion:
Thus, in the acid-catalyzed dehydration of alcohols to alkenes, the intermediate species formed is a carbocation.
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Community Answer
In the acid catalyzed dehydration of alcohols to alkenes, the intermed...

Corbocation as intermidiate
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In the acid catalyzed dehydration of alcohols to alkenes, the intermediate species formed isa)Free radicalb)Carbocationc)Carbaniond)CarbeneCorrect answer is option 'B'. Can you explain this answer?
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