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The maximum compressive stress at the top of a beam was 1600kg/cm2 and the corresponding tensile stress at its bottom was 800 kg/cm2. If the depth of the beam was 15 cm the neutral axis from the top will be
  • a)
    5 cm
  • b)
    10 cm
  • c)
    7.5 cm
  • d)
    12 cm
Correct answer is option 'B'. Can you explain this answer?
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The maximum compressive stress at the top of a beam was 1600kg/cm2 an...
Stress diagram By similar triangle
Xu = 10 cm
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The maximum compressive stress at the top of a beam was 1600kg/cm2 an...
Given data:
Maximum compressive stress at the top of the beam = 1600 kg/cm²
Corresponding tensile stress at the bottom of the beam = 800 kg/cm²
Depth of the beam = 15 cm

To find: Neutral axis from the top of the beam.

Formula used:
Neutral axis is given by the formula:
NA = (σ_c - σ_t) / (σ_c + σ_t) × d
where, σ_c = maximum compressive stress at the top of the beam
σ_t = corresponding tensile stress at the bottom of the beam
d = depth of the beam

Calculation:
Substituting the given values in the above formula, we get:
NA = (1600 - 800) / (1600 + 800) × 15
NA = 10 cm

Therefore, the neutral axis from the top of the beam is 10 cm.

Answer: Option B.
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