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A cylindrical container whose weight is 79 N is inverted and pressed into the water, as shown in Figure. Determine the force F needed to hold the container at the position shown.
Correct answer is 'Range: 59 to 60'. Can you explain this answer?
Verified Answer
A cylindrical container whose weight is 79 N is inverted and pressed ...
At the same level in a static fluid, pressure is same everywhere
So p1 = ρw × g × 0.2 (Gauge Pressure)
(p1)Gauge = 1962 Pa
For calculating force on container
F = pA − mg
F = 1962 × π / 4 × (0.3)2 − 79
F = 59.68 N
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Most Upvoted Answer
A cylindrical container whose weight is 79 N is inverted and pressed ...
At the same level in a static fluid, pressure is same everywhere
So p1 = ρw × g × 0.2 (Gauge Pressure)
(p1)Gauge = 1962 Pa
For calculating force on container
F = pA − mg
F = 1962 × π / 4 × (0.3)2 − 79
F = 59.68 N
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Community Answer
A cylindrical container whose weight is 79 N is inverted and pressed ...
At the same level in a static fluid, pressure is same everywhere
So p1 = ρw × g × 0.2 (Gauge Pressure)
(p1)Gauge = 1962 Pa
For calculating force on container
F = pA − mg
F = 1962 × π / 4 × (0.3)2 − 79
F = 59.68 N
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A cylindrical container whose weight is 79 N is inverted and pressed into the water, as shown in Figure. Determine the force F needed to hold the container at the position shown.Correct answer is 'Range: 59 to 60'. Can you explain this answer?
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