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Consider a container of circular cross-section (100 cm2). Initially 2 liters of oil (specific gravity 0.8) is poured in the container and then 3 liters of water is poured in it. Find out pressure, in Pa at a point 5 cm above the bottom surface of the container.
- a)2000 Pa
- b)2500 Pa
- c)3569 Pa
- d)4022 Pa
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Consider a container of circular cross-section (100 cm2). Initially 2 ...
Even though oil is poured first, but oil being lighter will go up and the water layer will settle at the bottom. Finally in equilibrium, the situation shall be as shown
pA = ρoil × g × 0.2 + ρw × g × 0.25
pA = 4022.1 Pa
Most Upvoted Answer
Consider a container of circular cross-section (100 cm2). Initially 2 ...
**Given:**
- The cross-section of the container is circular with an area of 100 cm^2.
- Initially, 2 liters of oil (specific gravity 0.8) is poured into the container.
- Then, 3 liters of water is poured into the container.
- We need to find the pressure at a point 5 cm above the bottom surface of the container.
**Solution:**
To find the pressure at a point inside the container, we can use the formula:
Pressure = density x gravity x height
Here, we need to consider the densities of both oil and water separately.
**Calculating the pressure due to oil:**
Density of oil = specific gravity x density of water
= 0.8 x 1000 kg/m^3
= 800 kg/m^3
Volume of oil = 2 liters = 0.002 m^3
Mass of oil = density x volume
= 800 kg/m^3 x 0.002 m^3
= 1.6 kg
Height of oil = 5 cm = 0.05 m
Pressure due to oil = density of oil x gravity x height
= 800 kg/m^3 x 9.81 m/s^2 x 0.05 m
= 392.4 Pa
**Calculating the pressure due to water:**
Density of water = 1000 kg/m^3
Volume of water = 3 liters = 0.003 m^3
Mass of water = density x volume
= 1000 kg/m^3 x 0.003 m^3
= 3 kg
Height of water = 5 cm = 0.05 m
Pressure due to water = density of water x gravity x height
= 1000 kg/m^3 x 9.81 m/s^2 x 0.05 m
= 490.5 Pa
**Total pressure at the point 5 cm above the bottom surface:**
Total pressure = pressure due to oil + pressure due to water
= 392.4 Pa + 490.5 Pa
= 882.9 Pa
Therefore, the pressure at a point 5 cm above the bottom surface of the container is approximately 882.9 Pa.
Since none of the given options match this value, there might be an error in the question or the options provided.
- The cross-section of the container is circular with an area of 100 cm^2.
- Initially, 2 liters of oil (specific gravity 0.8) is poured into the container.
- Then, 3 liters of water is poured into the container.
- We need to find the pressure at a point 5 cm above the bottom surface of the container.
**Solution:**
To find the pressure at a point inside the container, we can use the formula:
Pressure = density x gravity x height
Here, we need to consider the densities of both oil and water separately.
**Calculating the pressure due to oil:**
Density of oil = specific gravity x density of water
= 0.8 x 1000 kg/m^3
= 800 kg/m^3
Volume of oil = 2 liters = 0.002 m^3
Mass of oil = density x volume
= 800 kg/m^3 x 0.002 m^3
= 1.6 kg
Height of oil = 5 cm = 0.05 m
Pressure due to oil = density of oil x gravity x height
= 800 kg/m^3 x 9.81 m/s^2 x 0.05 m
= 392.4 Pa
**Calculating the pressure due to water:**
Density of water = 1000 kg/m^3
Volume of water = 3 liters = 0.003 m^3
Mass of water = density x volume
= 1000 kg/m^3 x 0.003 m^3
= 3 kg
Height of water = 5 cm = 0.05 m
Pressure due to water = density of water x gravity x height
= 1000 kg/m^3 x 9.81 m/s^2 x 0.05 m
= 490.5 Pa
**Total pressure at the point 5 cm above the bottom surface:**
Total pressure = pressure due to oil + pressure due to water
= 392.4 Pa + 490.5 Pa
= 882.9 Pa
Therefore, the pressure at a point 5 cm above the bottom surface of the container is approximately 882.9 Pa.
Since none of the given options match this value, there might be an error in the question or the options provided.
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Consider a container of circular cross-section (100 cm2). Initially 2 liters of oil (specific gravity 0.8) is poured in the container and then 3 liters of water is poured in it. Find out pressure, in Pa at a point 5 cm above the bottom surface of the container.a)2000 Pab)2500 Pac)3569 Pad)4022 PaCorrect answer is option 'D'. Can you explain this answer?
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Consider a container of circular cross-section (100 cm2). Initially 2 liters of oil (specific gravity 0.8) is poured in the container and then 3 liters of water is poured in it. Find out pressure, in Pa at a point 5 cm above the bottom surface of the container.a)2000 Pab)2500 Pac)3569 Pad)4022 PaCorrect answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Consider a container of circular cross-section (100 cm2). Initially 2 liters of oil (specific gravity 0.8) is poured in the container and then 3 liters of water is poured in it. Find out pressure, in Pa at a point 5 cm above the bottom surface of the container.a)2000 Pab)2500 Pac)3569 Pad)4022 PaCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a container of circular cross-section (100 cm2). Initially 2 liters of oil (specific gravity 0.8) is poured in the container and then 3 liters of water is poured in it. Find out pressure, in Pa at a point 5 cm above the bottom surface of the container.a)2000 Pab)2500 Pac)3569 Pad)4022 PaCorrect answer is option 'D'. Can you explain this answer?.
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Consider a container of circular cross-section (100 cm2). Initially 2 liters of oil (specific gravity 0.8) is poured in the container and then 3 liters of water is poured in it. Find out pressure, in Pa at a point 5 cm above the bottom surface of the container.a)2000 Pab)2500 Pac)3569 Pad)4022 PaCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Consider a container of circular cross-section (100 cm2). Initially 2 liters of oil (specific gravity 0.8) is poured in the container and then 3 liters of water is poured in it. Find out pressure, in Pa at a point 5 cm above the bottom surface of the container.a)2000 Pab)2500 Pac)3569 Pad)4022 PaCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Consider a container of circular cross-section (100 cm2). Initially 2 liters of oil (specific gravity 0.8) is poured in the container and then 3 liters of water is poured in it. Find out pressure, in Pa at a point 5 cm above the bottom surface of the container.a)2000 Pab)2500 Pac)3569 Pad)4022 PaCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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