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DIRECTIONS for the question: Solve the following question and mark the best possible option.
In parallelogram ABCD, AB < AD and ∠BAD = 60°. The bisector of ∠BAD intersects the side BC at point E. If AB = 4, what is the area of ΔABE?
  • a)
    4√3
  • b)
    8√3 / 3
  • c)
    16√2
  • d)
    8
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
DIRECTIONSfor the question:Solve the following question and mark the b...
Consider the following diagram:
Since ∠BAD = 60°, ∠BAE = 30°. Since AE is a transversal, ∠BAE = ∠BEA - 30°
Drop a perpendicular BF on to AE.
ΔBFA = ΔBFE and both are 30°, 60°, 90° triangles
In ΔBFA. since AB = 4.
We get BF = 2 and AF = 2√3
Since AF = EF = 2√3.
AE = 4√3
Thus the area of ΔABE = 1/2 x 2 x 4√3 = 4√3
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Most Upvoted Answer
DIRECTIONSfor the question:Solve the following question and mark the b...
Is parallel to CD and AD is parallel to BC. If angle BAD = 60°, find the measure of angle BCD.

Since AB is parallel to CD and AD is parallel to BC, we can conclude that angle BCD is equal to angle BAD. Therefore, angle BCD = 60°.
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DIRECTIONSfor the question:Solve the following question and mark the best possible option.In parallelogram ABCD, AB < AD and∠BAD = 60°. The bisector of∠BAD intersects the side BC at point E. If AB = 4, what is the area ofΔABE?a)4√3b)8√3 / 3c)16√2d)8Correct answer is option 'A'. Can you explain this answer?
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