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The left half of a simply supported beam of span “L” is loaded with u. d. l of w/meter run. The point of maximum B.M will occur at
  • a)
    mid-span
  • b)
    2L/3 from left support
  • c)
    3L/8 from left support
  • d)
    5L/8 from left support
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The left half of a simply supported beam of span “L” is loaded with u...
We know RA + RB = wL / 2
Taking moments about A
For maximum B.M, S. F must be change sign shear force at
x = RA − wx = 0
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The left half of a simply supported beam of span “L” is loaded with u...
Solution:

To find the point of maximum B.M, we need to determine the shear force (S.F) and bending moment (B.M) equations for the given beam.

Shear Force Equation:

At any distance x from the left support, the S.F is given by:

S.F = u × x

Bending Moment Equation:

At any distance x from the left support, the B.M is given by the area under the S.F curve up to that point:

B.M = ∫(0 to x) u × x dx

B.M = u/2 × x^2

To find the point of maximum B.M, we need to differentiate the B.M equation with respect to x and equate it to zero:

d(B.M)/dx = u × x = 0

x = 0 or x = L

Since the beam is loaded on the left half, the point of maximum B.M should lie in the left half of the span. So, we can discard x = L as a solution.

Therefore, the point of maximum B.M will occur at x = 0, which is the left support.

Answer: (a) Mid-span is incorrect. The correct answer is (c) 3L/8 from the left support.
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The left half of a simply supported beam of span “L” is loaded with u. d. l of w/meter run. The point of maximum B.M will occur ata) mid-spanb) 2L/3 from left supportc) 3L/8 from left supportd) 5L/8 from left supportCorrect answer is option 'C'. Can you explain this answer?
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