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Solve the following question and mark the best possible option.
X, Y and Z can do a piece of work in 30 days. They all three worked for 4 days and then X left. Y and Z continued the work and worked for 20 more days when Y left. Z worked for another 80 days and completed the work. In how many days can X alone complete the work if Z can complete it in 150 days?
  • a)
    30 days
  • b)
    60 days
  • c)
    40 days
  • d)
    50 days
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Solve the following question and mark the best possible option.X, Y an...
Assume the total work to be 1200 units. (LCM of all the numbers)
Then Z’s 1 day work = 8 units.
⇒ (X + Y + Z)’s 1 day work = 40 units.
X, Y, Z work together in the first 4 days
⇒Work done in the first 4 days = 40 × 4 = 160 units
Z alone works during the last 80 days
⇒Work done in the last 80 days = 80 × 8 = 640 units
Remaining work = 1200 – (160 + 640) = 400 units
This work is done by Y and Z in 20 days.
⇒ (Y + Z)’s 1 day work = 20 units
⇒X’s 1 day work = (X + Y + Z)’s 1 day work – (Y + Z)’s 1 day work = 40 units – 20 units = 20 units
⇒X can do the work of 1200 units in 60 days.
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Most Upvoted Answer
Solve the following question and mark the best possible option.X, Y an...
To solve this question, let's first determine the work efficiency of each person. Since X, Y, and Z can complete the work together in 30 days, their combined efficiency per day is 1/30.

Let's assume that X's efficiency per day is x, Y's efficiency per day is y, and Z's efficiency per day is z.

1. Work done by X, Y, and Z in 4 days:
Since they work together for 4 days, the total work done by them is (1/30) * 4 = 4/30.

2. Work done by Y and Z in 20 days:
After X leaves, Y and Z continue the work. So, their combined efficiency per day is (y + z). Therefore, the work done by Y and Z in 20 days is (y + z) * 20.

3. Work done by Z in 80 days:
After Y leaves, Z works alone. So, the work done by Z in 80 days is z * 80.

Now, let's determine the remaining work that X needs to complete alone.

Remaining work = Total work - Work done by X, Y, and Z in 4 days - Work done by Y and Z in 20 days - Work done by Z in 80 days

Remaining work = 1 - 4/30 - (y + z) * 20 - z * 80

Since Z can complete the work alone in 150 days, his efficiency per day is 1/150. Therefore, z = 1/150.

Substituting the value of z in the equation for remaining work:

Remaining work = 1 - 4/30 - (y + 1/150) * 20 - 1/150 * 80

Simplifying the equation, we get:

Remaining work = 1 - 2/15 - (y + 1/150) * 2 - 4/75

Now, we know that the remaining work needs to be completed by X alone. So, the equation becomes:

Remaining work = x * D

where D is the number of days X takes to complete the remaining work.

Substituting the value of remaining work in the equation:

x * D = 1 - 2/15 - (y + 1/150) * 2 - 4/75

Now, we need to find the value of D, which represents the number of days X takes to complete the work. To do that, we need to know the value of x and y, which are not given in the question.

Therefore, the given information is insufficient to determine the number of days X takes to complete the work.
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Solve the following question and mark the best possible option.X, Y and Z can do a piece of work in 30 days. They all three worked for 4 days and then X left. Y and Z continued the work and worked for 20 more days when Y left. Z worked for another 80 days and completed the work. In how many days can X alone complete the work if Z can complete it in 150 days?a)30 daysb)60daysc)40 daysd)50 daysCorrect answer is option 'B'. Can you explain this answer?
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