Question Description
n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer?.

Solutions for n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.

Here you can find the meaning of n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice n a strained material, normal stresses on two mutually perpendicular planes are σx and σy (both alike) accompanied by a shear stress τxy, one of the principal stresses will be zero, only if,a) τxy =b) τxy = √σx × σyc) τxy = σx × σyd) τxy =√σx2 × σy2Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.