Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > A rectangular channel 6.5 m wide carries a d...
Start Learning for Free
A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.
The longitudinal slope of the channel is
- a)0.00083
- b)0.00073
- c)0.00053
- d)0.00063
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under...
Width of rectangular channel
View all questions of this test
B = 6.5 m
Discharge Q = 18 m3/s
Normal depth = yn = 1.8 m
Manning’s n = 0.018
From Manning’s equation
S = 6.3033 × 10−4
Most Upvoted Answer
A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under...
Given data:
Width of rectangular channel (B) = 6.5 m
Discharge (Q) = 18 m3/s
Normal depth (Y) = 1.8 m
Manning’s n = 0.018
To find: Longitudinal slope of the channel
We can use Manning’s equation to find the slope of the channel.
Manning’s equation is given by:
Q = (1/n) * A * R2/3 * S1/2
Where,
Q = Discharge
n = Manning’s roughness coefficient
A = Cross-sectional area of flow
R = Hydraulic radius
S = Slope of the energy line
Cross-sectional area of flow (A) can be calculated as:
A = B * Y
Where,
B = Width of channel
Y = Normal depth
Hydraulic radius (R) can be calculated as:
R = A/P
Where,
P = Wetted perimeter
Wetted perimeter (P) can be calculated as:
P = B + 2Y
Substituting the above equations in Manning’s equation, we get:
Q = (1/n) * B * Y * [B + 2Y]2/3 * S1/2
Rearranging the equation to find slope (S), we get:
S = {Q / [(1/n) * B * Y * [B + 2Y]2/3]}2
Substituting the given values in the above equation, we get:
S = {18 / [(1/0.018) * 6.5 * 1.8 * [6.5 + 2(1.8)]2/3]}2
S = 0.00063
Therefore, the longitudinal slope of the channel is 0.00063. Hence, option (d) is the correct answer.
Width of rectangular channel (B) = 6.5 m
Discharge (Q) = 18 m3/s
Normal depth (Y) = 1.8 m
Manning’s n = 0.018
To find: Longitudinal slope of the channel
We can use Manning’s equation to find the slope of the channel.
Manning’s equation is given by:
Q = (1/n) * A * R2/3 * S1/2
Where,
Q = Discharge
n = Manning’s roughness coefficient
A = Cross-sectional area of flow
R = Hydraulic radius
S = Slope of the energy line
Cross-sectional area of flow (A) can be calculated as:
A = B * Y
Where,
B = Width of channel
Y = Normal depth
Hydraulic radius (R) can be calculated as:
R = A/P
Where,
P = Wetted perimeter
Wetted perimeter (P) can be calculated as:
P = B + 2Y
Substituting the above equations in Manning’s equation, we get:
Q = (1/n) * B * Y * [B + 2Y]2/3 * S1/2
Rearranging the equation to find slope (S), we get:
S = {Q / [(1/n) * B * Y * [B + 2Y]2/3]}2
Substituting the given values in the above equation, we get:
S = {18 / [(1/0.018) * 6.5 * 1.8 * [6.5 + 2(1.8)]2/3]}2
S = 0.00063
Therefore, the longitudinal slope of the channel is 0.00063. Hence, option (d) is the correct answer.
Attention Civil Engineering (CE) Students!
To make sure you are not studying endlessly, EduRev has designed Civil Engineering (CE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Civil Engineering (CE).
|
Explore Courses for Civil Engineering (CE) exam
|
|
Similar Civil Engineering (CE) Doubts
Top Courses for Civil Engineering (CE)View all
A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer?
Question Description
A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer?.
A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer?.
Solutions for A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.The longitudinal slope of the channel isa) 0.00083b) 0.00073c) 0.00053d) 0.00063Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
|
|
Explore Courses for Civil Engineering (CE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup