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A spherical pressure shell 3.8 meters diameter and 3 mm thick is subjected to an internal pressure ‘P’. The elastic limit of the shell material in simple tension is 260 MPa. The factor of safety is to 2.8. The internal pressure, if the failure of shell is to be prevented, according to maximum shear stress theory is
  • a)
    1.78 bar
  • b)
    2.932 bar
  • c)
    5.86 bar
  • d)
    2.33 bar
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A spherical pressure shell 3.8 meters diameter and 3 mm thick is subj...
σnoop = σ1 = σ2 =
Syt = 260 MPa
N = 2.8
According to MSST
Abs τmax
Abs τmax =
P = 2.932 bar
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Most Upvoted Answer
A spherical pressure shell 3.8 meters diameter and 3 mm thick is subj...
σnoop = σ1 = σ2 =
Syt = 260 MPa
N = 2.8
According to MSST
Abs τmax
Abs τmax =
P = 2.932 bar
Free Test
Community Answer
A spherical pressure shell 3.8 meters diameter and 3 mm thick is subj...
Calculation of Internal Pressure:
Given data:
- Diameter (D) = 3.8 meters
- Thickness (t) = 3 mm
- Elastic limit (σ) = 260 MPa
- Factor of safety (FoS) = 2.8

Step 1: Calculate hoop stress (σ_h):
Hoop stress is given by the formula: σ_h = P * D / (2 * t)
Substitute the values: σ_h = P * 3.8 / (2 * 0.003) = 633.33P

Step 2: Calculate maximum shear stress (τ_max):
Maximum shear stress is given by the formula: τ_max = σ_h / 2
Substitute the value of hoop stress: τ_max = 633.33P / 2 = 316.67P

Step 3: Calculate allowable shear stress (τ_allow):
Allowable shear stress is given by the formula: τ_allow = σ / FoS
Substitute the values: τ_allow = 260 MPa / 2.8 = 92.857 MPa

Step 4: Equate maximum shear stress to allowable shear stress:
316.67P = 92.857
Solve for P: P = 92.857 / 316.67 ≈ 0.292 bar
Therefore, the internal pressure required to prevent the failure of the shell according to the maximum shear stress theory is approximately 2.932 bar (option B).
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A spherical pressure shell 3.8 meters diameter and 3 mm thick is subjected to an internal pressure ‘P’. The elastic limit of the shell material in simple tension is 260 MPa. The factor of safety is to 2.8. The internal pressure, if the failure of shell is to be prevented, according to maximum shear stress theory isa) 1.78 barb) 2.932 barc) 5.86 bard) 2.33 barCorrect answer is option 'B'. Can you explain this answer?
Question Description
A spherical pressure shell 3.8 meters diameter and 3 mm thick is subjected to an internal pressure ‘P’. The elastic limit of the shell material in simple tension is 260 MPa. The factor of safety is to 2.8. The internal pressure, if the failure of shell is to be prevented, according to maximum shear stress theory isa) 1.78 barb) 2.932 barc) 5.86 bard) 2.33 barCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A spherical pressure shell 3.8 meters diameter and 3 mm thick is subjected to an internal pressure ‘P’. The elastic limit of the shell material in simple tension is 260 MPa. The factor of safety is to 2.8. The internal pressure, if the failure of shell is to be prevented, according to maximum shear stress theory isa) 1.78 barb) 2.932 barc) 5.86 bard) 2.33 barCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spherical pressure shell 3.8 meters diameter and 3 mm thick is subjected to an internal pressure ‘P’. The elastic limit of the shell material in simple tension is 260 MPa. The factor of safety is to 2.8. The internal pressure, if the failure of shell is to be prevented, according to maximum shear stress theory isa) 1.78 barb) 2.932 barc) 5.86 bard) 2.33 barCorrect answer is option 'B'. Can you explain this answer?.
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