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Metal is to be poured in a cubical cavity of 100 cm side made entirely in drag. The crosssection of the cope box is 200x 150 cm and height is 100 cm. If the densities of metal and sand are 7900 kg/m3 and 1600 kg/m3 respectively. The minimum weight required to be placed on cope in kN to prevent lifting of cope box is __________.
  • a)
    72
  • b)
    73
Correct answer is between ' 72, 73'. Can you explain this answer?
Most Upvoted Answer
Metal is to be poured in a cubical cavity of 100 cm side made entirel...
Metallastatic pressure on the mould = pgh
= 7900 x 9.81 x 1
= 77499 N/m2
Upward force exerted by molten metal on cope = 77499 x 1 x 1
= 77.499 kN
So, minimum weight to keep in cope box
= 77.499 - 4.8
= 72.699 kN
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Community Answer
Metal is to be poured in a cubical cavity of 100 cm side made entirel...
To prevent the lifting of the cope box, we need to calculate the minimum weight required to be placed on the cope box.

Given data:
- Density of metal (ρm) = 7900 kg/m3
- Density of sand (ρs) = 1600 kg/m3

First, let's calculate the volume of the metal poured in the cubical cavity.

Volume of the cubical cavity = (side)3 = (100 cm)3 = 1000000 cm3

Converting the volume to m3: 1000000 cm3 = 1 m3

Since the cross-section of the cope box is 200 cm x 150 cm, the volume of the cope box can be calculated as follows:

Volume of the cope box = (cross-section area) x (height)
= (200 cm x 150 cm) x 100 cm
= 3000000 cm3

Converting the volume to m3: 3000000 cm3 = 3 m3

The weight of the metal poured in the cubical cavity can be calculated using the formula:

Weight of the metal = Volume of the metal x Density of the metal
= 1 m3 x 7900 kg/m3
= 7900 kg

Next, we need to calculate the weight of the sand in the cope box. The weight of the sand can be calculated using the formula:

Weight of the sand = Volume of the sand x Density of the sand
= 3 m3 x 1600 kg/m3
= 4800 kg

To prevent the lifting of the cope box, the minimum weight required to be placed on the cope box is the difference between the weight of the metal and the weight of the sand.

Minimum weight required = Weight of the metal - Weight of the sand
= 7900 kg - 4800 kg
= 3100 kg

Finally, we need to convert the weight from kg to kN. Since 1 kN = 1000 kg, the minimum weight required can be calculated as:

Minimum weight required = 3100 kg / 1000
= 3.1 kN

Therefore, the minimum weight required to be placed on the cope box to prevent lifting is 3.1 kN.
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Metal is to be poured in a cubical cavity of 100 cm side made entirely in drag. The crosssection of the cope box is 200x 150 cm and height is 100 cm. If the densities of metal and sand are 7900 kg/m3 and 1600 kg/m3 respectively. The minimum weight required to be placed on cope in kN to prevent lifting of cope box is __________.a) 72b) 73Correct answer is between ' 72, 73'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Metal is to be poured in a cubical cavity of 100 cm side made entirely in drag. The crosssection of the cope box is 200x 150 cm and height is 100 cm. If the densities of metal and sand are 7900 kg/m3 and 1600 kg/m3 respectively. The minimum weight required to be placed on cope in kN to prevent lifting of cope box is __________.a) 72b) 73Correct answer is between ' 72, 73'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Metal is to be poured in a cubical cavity of 100 cm side made entirely in drag. The crosssection of the cope box is 200x 150 cm and height is 100 cm. If the densities of metal and sand are 7900 kg/m3 and 1600 kg/m3 respectively. The minimum weight required to be placed on cope in kN to prevent lifting of cope box is __________.a) 72b) 73Correct answer is between ' 72, 73'. Can you explain this answer?.
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