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A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius is
- a)1.25 m
- b)1.14 m
- c)1.05 m
- d)1.0 m
Correct answer is option 'D'. Can you explain this answer?
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A rectangular channel is 4 m wide and 2.5 m deep water is flowing in ...
= 1.024 m
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A rectangular channel is 4 m wide and 2.5 m deep water is flowing in ...
= 1.024 m
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A rectangular channel is 4 m wide and 2.5 m deep water is flowing in ...
The Problem:
We are given a rectangular channel with a width of 4 m and a depth of 2.5 m. Water is flowing in the channel with a depth of 2.1 m. We need to calculate the hydraulic radius of the channel.
Understanding the Hydraulic Radius:
The hydraulic radius is a measure of the efficiency of a channel in carrying water. It is defined as the ratio of the cross-sectional area of flow to the wetted perimeter of the channel.
Solution:
To find the hydraulic radius, we need to calculate the cross-sectional area of flow and the wetted perimeter.
Calculating the Cross-Sectional Area of Flow:
The cross-sectional area of flow can be calculated using the formula:
A = width × depth
Given that the width of the channel is 4 m and the depth of flow is 2.1 m, we can substitute these values into the formula:
A = 4 m × 2.1 m = 8.4 m²
Calculating the Wetted Perimeter:
The wetted perimeter is the perimeter of the cross-section of flow in contact with water. In the case of a rectangular channel, the wetted perimeter can be calculated using the formula:
P = 2 × width + 2 × depth
Substituting the given values, we get:
P = 2 × 4 m + 2 × 2.1 m = 8 m + 4.2 m = 12.2 m
Calculating the Hydraulic Radius:
Finally, we can calculate the hydraulic radius using the formula:
R = A / P
Substituting the values we have calculated:
R = 8.4 m² / 12.2 m = 0.6885 m
Conclusion:
The hydraulic radius of the rectangular channel is 0.6885 m, which can be approximated to 0.69 m. Therefore, none of the given options (a, b, c, d) matches the correct answer.
We are given a rectangular channel with a width of 4 m and a depth of 2.5 m. Water is flowing in the channel with a depth of 2.1 m. We need to calculate the hydraulic radius of the channel.
Understanding the Hydraulic Radius:
The hydraulic radius is a measure of the efficiency of a channel in carrying water. It is defined as the ratio of the cross-sectional area of flow to the wetted perimeter of the channel.
Solution:
To find the hydraulic radius, we need to calculate the cross-sectional area of flow and the wetted perimeter.
Calculating the Cross-Sectional Area of Flow:
The cross-sectional area of flow can be calculated using the formula:
A = width × depth
Given that the width of the channel is 4 m and the depth of flow is 2.1 m, we can substitute these values into the formula:
A = 4 m × 2.1 m = 8.4 m²
Calculating the Wetted Perimeter:
The wetted perimeter is the perimeter of the cross-section of flow in contact with water. In the case of a rectangular channel, the wetted perimeter can be calculated using the formula:
P = 2 × width + 2 × depth
Substituting the given values, we get:
P = 2 × 4 m + 2 × 2.1 m = 8 m + 4.2 m = 12.2 m
Calculating the Hydraulic Radius:
Finally, we can calculate the hydraulic radius using the formula:
R = A / P
Substituting the values we have calculated:
R = 8.4 m² / 12.2 m = 0.6885 m
Conclusion:
The hydraulic radius of the rectangular channel is 0.6885 m, which can be approximated to 0.69 m. Therefore, none of the given options (a, b, c, d) matches the correct answer.
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A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius isa) 1.25 mb) 1.14 mc) 1.05 md) 1.0 mCorrect answer is option 'D'. Can you explain this answer?
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A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius isa) 1.25 mb) 1.14 mc) 1.05 md) 1.0 mCorrect answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius isa) 1.25 mb) 1.14 mc) 1.05 md) 1.0 mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius isa) 1.25 mb) 1.14 mc) 1.05 md) 1.0 mCorrect answer is option 'D'. Can you explain this answer?.
A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius isa) 1.25 mb) 1.14 mc) 1.05 md) 1.0 mCorrect answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius isa) 1.25 mb) 1.14 mc) 1.05 md) 1.0 mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius isa) 1.25 mb) 1.14 mc) 1.05 md) 1.0 mCorrect answer is option 'D'. Can you explain this answer?.
Solutions for A rectangular channel is 4 m wide and 2.5 m deep water is flowing in the channel for a depth of 2.1 m. The hydraulic radius isa) 1.25 mb) 1.14 mc) 1.05 md) 1.0 mCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
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