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The depth of flow for maximum velocity in a circular channel section with diameter equal to 1.5 m is
- a)0.75 m
- b)1.065 m
- c)1.215 m
- d)1.425 m
Correct answer is option 'C'. Can you explain this answer?
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The depth of flow for maximum velocity in a circular channel section w...
**Explanation:**
When the flow in a circular channel is at maximum velocity, it is known as critical flow. In critical flow, the water surface is at its lowest point, resulting in the maximum velocity.
To determine the depth of flow for maximum velocity in a circular channel section, we can use the concept of critical depth. Critical depth is the depth of flow at which the specific energy is minimum for a given discharge. It is calculated using the Manning's equation or the Chezy's equation.
In this case, we are given the diameter of the circular channel section as 1.5 m.
To find the depth of flow for maximum velocity, we can use the concept of critical depth. Critical depth (dc) can be calculated using the following formula:
dc = 0.81 * D
Where:
dc = critical depth
D = diameter of the circular channel section
Substituting the given value of D = 1.5 m into the formula, we get:
dc = 0.81 * 1.5
= 1.215 m
Therefore, the depth of flow for maximum velocity in a circular channel section with a diameter of 1.5 m is 1.215 m.
Hence, the correct answer is option C) 1.215 m.
When the flow in a circular channel is at maximum velocity, it is known as critical flow. In critical flow, the water surface is at its lowest point, resulting in the maximum velocity.
To determine the depth of flow for maximum velocity in a circular channel section, we can use the concept of critical depth. Critical depth is the depth of flow at which the specific energy is minimum for a given discharge. It is calculated using the Manning's equation or the Chezy's equation.
In this case, we are given the diameter of the circular channel section as 1.5 m.
To find the depth of flow for maximum velocity, we can use the concept of critical depth. Critical depth (dc) can be calculated using the following formula:
dc = 0.81 * D
Where:
dc = critical depth
D = diameter of the circular channel section
Substituting the given value of D = 1.5 m into the formula, we get:
dc = 0.81 * 1.5
= 1.215 m
Therefore, the depth of flow for maximum velocity in a circular channel section with a diameter of 1.5 m is 1.215 m.
Hence, the correct answer is option C) 1.215 m.
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The depth of flow for maximum velocity in a circular channel section with diameter equal to 1.5 m isa)0.75 mb)1.065 mc)1.215 md)1.425 mCorrect answer is option 'C'. Can you explain this answer?
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