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A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.
- a)12
- b)8
- c)4
- d)14
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial int...
P = 50 kW, N = 1400 r.p.m,
pmax = 0.15 N/mm2,μ = 0.12, r2 = 80 mm,
r1 = r2/0.7
Axial resisting force per pair of contact surfaces,
F =2πpmax x r2(r1 - r2)
= 2585 N
Friction torque per pair of contact surfaces
=30.13 N-m
Number of pairs of friction surfaces required,
= 11.3 say12
This can be achieved by mounting 7 discs (n1) on the driving shaft and 6 discs (n2) on the driven shaft, such that the number of pairs of friction surfaces.
Most Upvoted Answer
A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial int...
Given data:
Power transmission = 50 kW
Speed = 1400 rpm
Axial intensity of pressure = 0.15 N/mm2
Coefficient of friction = 0.12
Inner radius of the disc = 80 mm
Inner radius is 0.7 times the outer radius
To determine the number of discs required to transmit the given power, we need to use the formula for power transmission in a multi-disc clutch:
P = (π/2) * μ * (D2^2 – D1^2) * N * v
Where,
P = Power transmission (kW)
μ = Coefficient of friction
D1 = Inner diameter of the clutch (mm)
D2 = Outer diameter of the clutch (mm)
N = Number of discs
v = Peripheral velocity of the clutch (m/s)
First, we need to convert the power and speed to SI units:
Power transmission = 50,000 W
Speed = (1400/60) = 23.33 rps
Next, we can calculate the outer diameter of the clutch:
Inner radius = 80 mm
Inner radius is 0.7 times the outer radius
Outer radius = (80/0.7) = 114.29 mm
Outer diameter = 2 * Outer radius = 228.57 mm
Now, we can calculate the peripheral velocity of the clutch:
v = (π * D2 * N * v)/60
v = (π * 228.57 * N * 23.33)/60
v = 359.68 * N m/s
Substituting the values in the power transmission formula and solving for N:
50,000 = (π/2) * 0.12 * (228.57^2 – 80^2) * N * 359.68N
N = 12
Therefore, the number of discs required to transmit the given power is 12.
Power transmission = 50 kW
Speed = 1400 rpm
Axial intensity of pressure = 0.15 N/mm2
Coefficient of friction = 0.12
Inner radius of the disc = 80 mm
Inner radius is 0.7 times the outer radius
To determine the number of discs required to transmit the given power, we need to use the formula for power transmission in a multi-disc clutch:
P = (π/2) * μ * (D2^2 – D1^2) * N * v
Where,
P = Power transmission (kW)
μ = Coefficient of friction
D1 = Inner diameter of the clutch (mm)
D2 = Outer diameter of the clutch (mm)
N = Number of discs
v = Peripheral velocity of the clutch (m/s)
First, we need to convert the power and speed to SI units:
Power transmission = 50,000 W
Speed = (1400/60) = 23.33 rps
Next, we can calculate the outer diameter of the clutch:
Inner radius = 80 mm
Inner radius is 0.7 times the outer radius
Outer radius = (80/0.7) = 114.29 mm
Outer diameter = 2 * Outer radius = 228.57 mm
Now, we can calculate the peripheral velocity of the clutch:
v = (π * D2 * N * v)/60
v = (π * 228.57 * N * 23.33)/60
v = 359.68 * N m/s
Substituting the values in the power transmission formula and solving for N:
50,000 = (π/2) * 0.12 * (228.57^2 – 80^2) * N * 359.68N
N = 12
Therefore, the number of discs required to transmit the given power is 12.
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A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer?
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A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer?.
A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer?.
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A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A multi-disc clutch transmits 50 kW of power at 1400 r.p.m. Axial intensity of pressure is not to exceed 0.15 N/mm2 , and the coefficient of friction for the friction surfaces is 0.12. The inner radius of the disc is 80 mm, and is 0.7 times the outer radius. Determine the number of discs required to transmit the given power. Assume uniform wear condition.a) 12b) 8c) 4d) 14Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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