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A small surface of area emits radiation as a blackbody. A fraction of this energy emitted is received by another small area Oriented as shown in figure.
A1 = 2 cm2
The rate at which radiation emitted by surface 1 strikes is measured to be 274 x 10-6 W. Determine the surface temperature of in K?
  • a)
    550
  • b)
    555
Correct answer is between ' 550, 555'. Can you explain this answer?
Verified Answer
A small surface of area emits radiation as a blackbody. A fraction of...
As surface 1 is a black surface, the energy leaving the surface is only the energy emitted by the surface.
Also by definition of black surface (diffuse characteristics)
Ic1 = σT14
274 x 10-6 W = 5.67 x 10-1 W/m2- K4 x T14 x ( 2cm2 x 6 cm2) x cos 60o x cos 30o /(100 cm)2
274 x 10-6 = 5.67 x 10-8 x 12 x 10-4/ 104 x 1/2 x ✓3/4 x T14
274 x 10-6 x 10-8 x 4 / 5.67 x 12 x ✓3 = T14
∴ T14 = 9.30 x 1010
T1 = 552.23 K
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Most Upvoted Answer
A small surface of area emits radiation as a blackbody. A fraction of...
As surface 1 is a black surface, the energy leaving the surface is only the energy emitted by the surface.
Also by definition of black surface (diffuse characteristics)
Ic1 = σT14
274 x 10-6 W = 5.67 x 10-1 W/m2- K4 x T14 x ( 2cm2 x 6 cm2) x cos 60o x cos 30o /(100 cm)2
274 x 10-6 = 5.67 x 10-8 x 12 x 10-4/ 104 x 1/2 x ✓3/4 x T14
274 x 10-6 x 10-8 x 4 / 5.67 x 12 x ✓3 = T14
∴ T14 = 9.30 x 1010
T1 = 552.23 K
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Community Answer
A small surface of area emits radiation as a blackbody. A fraction of...
As surface 1 is a black surface, the energy leaving the surface is only the energy emitted by the surface.
Also by definition of black surface (diffuse characteristics)
Ic1 = σT14
274 x 10-6 W = 5.67 x 10-1 W/m2- K4 x T14 x ( 2cm2 x 6 cm2) x cos 60o x cos 30o /(100 cm)2
274 x 10-6 = 5.67 x 10-8 x 12 x 10-4/ 104 x 1/2 x ✓3/4 x T14
274 x 10-6 x 10-8 x 4 / 5.67 x 12 x ✓3 = T14
∴ T14 = 9.30 x 1010
T1 = 552.23 K
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A small surface of area emits radiation as a blackbody. A fraction of this energy emitted is received by another small area Oriented as shown in figure.A1 = 2 cm2The rate at which radiation emitted by surface 1 strikes is measured to be 274 x 10-6 W. Determine the surface temperature of in K?a) 550b) 555Correct answer is between ' 550, 555'. Can you explain this answer?
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A small surface of area emits radiation as a blackbody. A fraction of this energy emitted is received by another small area Oriented as shown in figure.A1 = 2 cm2The rate at which radiation emitted by surface 1 strikes is measured to be 274 x 10-6 W. Determine the surface temperature of in K?a) 550b) 555Correct answer is between ' 550, 555'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A small surface of area emits radiation as a blackbody. A fraction of this energy emitted is received by another small area Oriented as shown in figure.A1 = 2 cm2The rate at which radiation emitted by surface 1 strikes is measured to be 274 x 10-6 W. Determine the surface temperature of in K?a) 550b) 555Correct answer is between ' 550, 555'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small surface of area emits radiation as a blackbody. A fraction of this energy emitted is received by another small area Oriented as shown in figure.A1 = 2 cm2The rate at which radiation emitted by surface 1 strikes is measured to be 274 x 10-6 W. Determine the surface temperature of in K?a) 550b) 555Correct answer is between ' 550, 555'. Can you explain this answer?.
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