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A journal bearing of diameter 25 cm and length 40 cm carries a load of 150 kN. The average bearing pressure is
  • a)
    1.5 kN/cm2
  • b)
    15 kN/cm2
  • c)
    150 kN/cm2
  • d)
    None of the above
Correct answer is option 'D'. Can you explain this answer?
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The average bearing pressure is given by the formula:

Average bearing pressure = Load / (π * (diameter/2) * length)

Here, the diameter of the journal bearing is given as 25 cm and the length is given as 40 cm. The load carried by the bearing is given as 150 kN.

Let's calculate the average bearing pressure using the given values:

Average bearing pressure = 150 kN / (π * (25 cm / 2) * 40 cm)

= 150000 N / (3.14 * (12.5 cm) * 40 cm)

= 150000 N / (3.14 * 500 cm^2)

= 150000 N / 1570 cm^2

= 95.54 N/cm^2

Therefore, the average bearing pressure is 95.54 N/cm^2.

Since none of the options given in the question matches the calculated value, the correct answer is "None of the above" (Option D).

In this case, the correct answer is "None of the above" because the calculated average bearing pressure is not equal to any of the options given in the question.
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A journal bearing of diameter 25 cm and length 40 cm carries a load of 150 kN. The average bearing pressure isa) 1.5 kN/cm2b) 15 kN/cm2c) 150 kN/cm2d) None of the aboveCorrect answer is option 'D'. Can you explain this answer?
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