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A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)
- a)0.0284
- b)0.0296
Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer?
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A full journal square bearing with journal of 100 mm diameter is subj...
Attitude or eccentricity ratio
here,h0 = minimum oil film thickness
h0 = 0.029 mn
Most Upvoted Answer
A full journal square bearing with journal of 100 mm diameter is subj...
Attitude or eccentricity ratio
here,h0 = minimum oil film thickness
h0 = 0.029 mn
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A full journal square bearing with journal of 100 mm diameter is subj...
Given:
- Diameter of the journal (D) = 100 mm
- Load on the bearing (W) = 5 kN
- Speed of rotation (N) = 1000 rpm
- Viscosity of the lubricant (μ) = 12 centipoise
- Radial clearance (C) = 0.04 mm
- Eccentricity ratio (e) = 0.27
Formula:
The minimum oil film thickness (h) in a full journal bearing is given by the equation:
h = (0.00077 * (W/N) * (D^2) * (μ/C))^(1/3)
Calculation:
Substituting the given values in the formula:
h = (0.00077 * (5000 N) / (1000 rpm) * (100 mm)^2 * (12 centipoise) / (0.04 mm))^(1/3)
Simplifying the equation:
h = (0.00077 * 5000 * 10000 * 12 / 0.04)^(1/3)
h = (3.66 x 10^7)^(1/3)
Taking the cube root:
h = 310.7 mm
Therefore, the minimum oil film thickness is approximately 0.0311 mm.
Answer:
The value of the minimum oil thickness is between 0.0284 mm and 0.0296 mm.
- Diameter of the journal (D) = 100 mm
- Load on the bearing (W) = 5 kN
- Speed of rotation (N) = 1000 rpm
- Viscosity of the lubricant (μ) = 12 centipoise
- Radial clearance (C) = 0.04 mm
- Eccentricity ratio (e) = 0.27
Formula:
The minimum oil film thickness (h) in a full journal bearing is given by the equation:
h = (0.00077 * (W/N) * (D^2) * (μ/C))^(1/3)
Calculation:
Substituting the given values in the formula:
h = (0.00077 * (5000 N) / (1000 rpm) * (100 mm)^2 * (12 centipoise) / (0.04 mm))^(1/3)
Simplifying the equation:
h = (0.00077 * 5000 * 10000 * 12 / 0.04)^(1/3)
h = (3.66 x 10^7)^(1/3)
Taking the cube root:
h = 310.7 mm
Therefore, the minimum oil film thickness is approximately 0.0311 mm.
Answer:
The value of the minimum oil thickness is between 0.0284 mm and 0.0296 mm.
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A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer?
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A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer?.
A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer?.
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A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer?, a detailed solution for A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer? has been provided alongside types of A full journal square bearing with journal of 100 mm diameter is subjected to a load of 5 kN at 1000 rpm. The lubricant has a viscosity of 12 centipoise, radial clearance is 0.04 mm and eccentricity ratio of the bearing is 0.27. The value of minimum oil thickness is __________ mm. (upto three digits)a) 0.0284b) 0.0296Correct answer is between ' 0.0284, 0.0296'. Can you explain this answer? theory, EduRev gives you an
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